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Goryan [66]
3 years ago
14

When the concentration of a substance higher on one side of the cells selectively permeable membrane, certain molecules may move

by osmosis or diffusion through the membrane without the cell using any energy. This process is called
A.passive transport
B.active transport
C. Mitosis
D. Replication
Biology
1 answer:
grin007 [14]3 years ago
8 0

Answer:

A.

Explanation:

osmosis and diffusion are both passive transport bc it doesnt require energy and only moves down cocentration gradient, never against concertration gradient. Give me a brainliest if i helped! ♡

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What information would you need to know in order to make an accurate classification of these organisms?
77julia77 [94]

Answer:

Following information are needed to classify an organism.

1. Unicellular or multicellular : First we have to see that from how many cells the body of organisms formed.

2. Composition of cell wall: Secondly we have to see the cell wall composition.

3. Prokaryotic or eukaryotic cell: We have to see the nucleus of organisms, if it has nucleus we can say that it is a eukaryotic cell.

4. Mode of nutrition: Mode of nutrition means is the organisms is autotroph or heterotroph.

If they have similarities, so it is placed in one group. If not so it is placed in different group or kingdom.

8 0
3 years ago
Una solución de 0.204 M de NaOH seutiliza para neutralizar 50 mL de una solución de H3PO4. Si se necesitaron 16.4 mL de la soluc
vfiekz [6]

Answer: 0.05 M

Explanation:

Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.

En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).

Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:

Concentración inicial x Volumen inicial = Concentración final x Volumen final.

Concentración inicial: 0.204 M

Volumen inicial: 16.4 mL

Concentración final: ?

Volumen final: 50 mL + 16.4 mL = 66.4 mL

Reemplazamos los valores en la ecuación:

0.204 M x 16.4 mL = Concentración final x 66.4 mL

La molaridad de la solución de H3PO4 es de 0.05 M.

7 0
3 years ago
The name for continents in one landmass surrounded by gigantic ocean
andre [41]
A Pangaea...Hope This Helped U ♡
7 0
3 years ago
Which of the following is a major trend in land plant evolution? Group of answer choices the trend toward a gametophyte-dominate
Leviafan [203]

Answer:

trend toward a sporophyte-dominated life cycle

the trend toward larger gametophytes

Explanation:

<em>The major trend in the evolution of land plants is the domination of the sporophytic phase in the life cycle and alternation of generation. It also moves towards a larger gametophytes</em>

In lower plants, the gameophyte phase was dominant in the life cycle while in bryophyte, both gametophyte and sporophyte phase are co-dependent.

The sporophyte phase is the diploid phase while the gametophyte phase is the haploid phase.

Also, the gameotyptic stages are quite microscopic (usually in the form of spores) in lower plants while they become bigger in land plants (in the form of ovary and pollen) although with fewer cells.

8 0
3 years ago
Which of the following can be used to determine the rate of enzyme-catalyzed reactions?
LekaFEV [45]

Answer:

Enzyme catalysis is detected by measuring either the appearance of product or disappearance of reactants. To measure something, you must be able to see it. Enzyme assays are tests developed to measure enzyme activity by measuring the change in concentration of a detectable substance.

7 0
3 years ago
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