Can someone help me? really easy fraction question!

Mathematics

1 answer:

kvasek [131]3 years ago

5 0

Answer:

2. 1/24

Step-by-step explanation:

1. six streets, (1/6)

2. north and south (1/2)

3. west and east (1/2)

Multiply all the above fractions together to get final answer!

You might be interested in

Write an equation of a line with the given slope and y-intercept. m = 1, b = 4 a) y = x – 4 b) y = –1x + 4 c) y = x + 4 d) y = 4

lubasha [3.4K]

Answer:

y = x+4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 1x+4

y = x+4

3 0

3 years ago

Read 2 more answers

Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans

tatyana61 [14]

Answer:

3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

$\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}$

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

$\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}$