Rectangle A is enlarged to create Rectangle B.

Mathematics

1 answer:

vaieri [72.5K]2 years ago

7 0

Answer:

itz 5

Step-by-step explanation:

i took quiz

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Solve 3x − 2y = −21 and 2x + 5y = 5 using elimination

nydimaria [60]

Answer:

x = -5 and y = 3

Step-by-step explanation:

There are two equations :

3x − 2y = −21 ....(1)

2x + 5y = 5 ......(2)

Multiply equation (1) by 2 and equation (2) by 3.

6x - 4y = -42 ...(3)

6x + 15y = 15 ....(4)

Subtract equation (4) from (3) :

6x - 4y - (6x + 15y) = -42 -15

-4y -15y = -57

-19y = -57

y = 3

Put y = 3 in equation (2) :

2x + 5(3) = 5

2x = 5-15

2x = -10

x = -5

So, the value of x is (-5) and y = 3.

6 0

2 years ago

1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )

sergeinik [125]

Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are $\frac{10!}{(10-6)!6!}$ ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are $\frac{7!}{(7-1)!1!}$ ways of choosing the first winner, which is 7 ways
There are $\frac{6!}{(6-1)!1!}$ ways of choosing the second winner, which is 6 ways
There are $\frac{5!}{(5-1)!1!}$ ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is $\frac{15}{31}$ × $\frac{9}{30}$ , which equals to $\frac{9}{62}$

The probability of eating two green candies is $\frac{7}{31}$ × $\frac{6}{30}$ which equals to $\frac{7}{155}$