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Step2247 [10]
4 years ago
12

Which equation is correct?

Mathematics
1 answer:
Ierofanga [76]4 years ago
6 0

Answer:

cos h=x/h=30/g=60/x=rad3/2...y=1/2/z=1

Step-by-step explanation:

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\huge\boxed{Solution=B,(3,2)}

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3 years ago
The sunglasses cost €70
Westkost [7]

Answer:

 70 * 0.895 = 62.65

OR

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-Cross-multiply

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3 years ago
Is this a polynomial function? I need to know ASAP
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Yes it is.

Step-by-step explanation:

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6 0
4 years ago
Use the equation and type the ordered-pairs. y=3^x
aleksandrvk [35]

The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)

<h3>How to type the ordered pairs?</h3>

The equation is given as:

y = 3^x

Let x = 0, 1 and 2

y = 3^0 = 1

y = 3^1 = 3

y = 3^2 = 9

So, we have the following ordered pairs (0,1), (1,3) and (2,9)

Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)

Read more about exponential functions at:

brainly.com/question/2456547

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