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3 years ago

A shoe store displayed 75 pairs of shoes on 12 shelves. How many pairs of shoes could the store display on eight shelves.

Mathematics

2 answers:

yanalaym [24]3 years ago

8 0

50 pairs of shoes since 75/12 is 6.25 and then multiply 6.25x8

ASHA 777 [7]3 years ago

3 0

Answer:

8 shelves can fit 50 shoes.

Step-by-step explanation:

1st. Multiply 75 and 12. You should get 6.25.

2nd. Multiply 6.25 and 8, since you need to figure out to find out how many shoes can fit in 8 shelves. You should get 50 shoes.

50 shoes can fit in 8 shelves.

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Its 18. Because if u divide 5 to 2 u get 2.5. Which is their difference in the thing. And basically it’s 45:green apples so u just divide 45 to 2.5 and u get 18

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3 years ago

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pashok25 [27]

Answer:

Step-by-step explanation:

1/2(6x5) = 15

15x4 = 60

5x5= 25

25 + 60 = 85

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3 years ago

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If tñ=2ñ+3, find S10

Allisa [31]

Answer:

$S_{10}=280$

Step-by-step explanation:

Given that,

$t_n=2n+3$ ...(1)

We need to find the value of $S_{10}$ .

Put n = 1 to find the first term.

$t_1=2(1)+3=5$

Put n = 2 to find the second term.

$t_2=2(2)+3=7$

Put n = 3 to find the third term.

$t_3=2(3)+3=9$

Put n = 10 to find the tenth term.

$t_{10}=2(10)+3=23$

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

$S_=\dfrac{n}{2}(a+a_n)$

We have, n = 10, a = 5 and $a_n=23$

So,

$S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280$

So, the value of $S_{10}$ is equal to 280.

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3 years ago

Devon is asked to draw a triangle with the following specifications:

N76 [4]

The answer should be c

5 0

2 years ago

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An ordinary Fair die is a cube with the numbers 1 through 6 on the sides represented by painted spots imagine that such a die is

Hoochie [10]

Answer: Probability of, Event A = 5/18

Event B = 1/2

Step-by-step explanation:

Since, The probability of an event = Number of outcomes of the event/ total number of outcomes.

Since, If a fair dire rolled two times then the total number of outcomes, n(S) = 6 × 6 = 36

And, Event A: The sum is greater than 8.

So, possible outcomes are, ( 3,6), (4,5), (4,6), (5,5), (5,6), (5,4), (6,6), (6,5), (6,4), (6,3)

Thus, n(A) = 10

Since, Probability of event A,

P(A) = n(A)/n(S) = 10/36 = 5/18

Therefore, P(A)= 5/18

Now, Event B: The sum is an even number.

So, possible outcomes are, (1,1),(1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,6), (4,2), (4,4), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)

Thus, n(B)= 18

Since, Probability of event B,

P(B)= n(B)/n(S) = 18/36 = 1/2

Therefore, P(B)= 1/2

7 0

2 years ago