Solution:
As given Rectangle ABCD is reflected over the y- axis.
When a shape or geometrical figure is reflected through a line it's distance that is distance of image from line and distance of Pre-image from that line is always same.Also perpendicular distance of vertices of any polygon that is considered for reflection has same distance from that line after reflection and before reflection.
Suppose the coordinate of A be (x,y) and considering Rectangle A B CD lie in first quadrant then when it is reflected through y - axis that is through the line x=0, it's new coordinate will become A' (-x,y).
If rectangle is in second quadrant having Vertices that is vertices of A (-x,y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,y).
If rectangle is in third quadrant having Vertices that is vertices of A (-x,-y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,-y).
If rectangle is in fourth quadrant having Vertices that is vertices of A (x,-y) then reflected over line that is x=0,→y axis then Vertices of A' (-x,-y).
Answer:
B) rose bush: $8, pot of ivy: $11
Step-by-step explanation:
12(8) + 13(11) = 239
remove parentheses: (a) = a
= 12 * 8 + 13 * 11
multiply the numbers: 12 * 8 = 96
= 96 + 13 * 11
multiply the numbers: 13 * 11 = 143
= 96 + 143
add the numbers: 96 + 143 = 239
= 239
30 because 18 and the plain goes into 12 which is 30
I think
Answer:
The answer is C. 10
Step-by-step explanation:
That will be a line passing through the center and perpendicular to, a line joining the 2 points.