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OleMash [197]
3 years ago
6

99 POINTS!!! JUST ANSWER THIS QUESTION, PLEASE!!!

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0

Hi!

I would approach this question by first looking at where the parallelogram is located, by graphing the image. I did so and drew a rough image on Paint (See attached image)

To get the part where the diagonals intersect, I would find the midpoint of the line between points (1, 3) and (5,-9) (or the other pair). The reason is a parallelogram's diagonals always bisect each other, meaning the point they intersect is always the middle of the two diagonals.

Therefore, you can find the midpoint of a diagonal, between (1, 3) and (5, -9). The midpoint theorem is (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}.

Take the points (1, 3) and (5, -9), and fill them in.

(\frac{1 + 5}{2} , \frac{3 - 9}{2})

Then solve.

(\frac{6}{2}, \frac{-6}{2})

(3, -3)

If you'd like to check the other midpoint:

Take the points, (8, 3) and (-2, -9)

(\frac{8 - 2}{2}, \frac{3 - 9}{2})

Then solve.

(\frac{6}{2} , \frac{-6}{2})

(3, -3)

They're the same, so that answer is correct.

Hope this helps!

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3 years ago
In triangle ACE, P is the centroid, PF = 6 , and AD = 15 15. Find the measures of PC and AP. Enter your answers as numbers.
xxTIMURxx [149]

Answer:

PC = 12 units

AP = 10 units

Step-by-step explanation:

  • The centroid of a triangle is the intersection of the three medians of the triangle
  • Each median connecting a vertex with the midpoint of the opposite side
  • The centroid divides each median into two parts, which are always in the ratio 2: 1 from the vertex

In ΔACE

∵ P is the centroid of it

∴ P divides CF the ratio 2: 1 from C

∴ PC = 2 PF

∵ PF = 6 units

∴ PC = 2(6)

∴ PC = 12 units

∵ P divides AD at the ratio 2: 1 from A

→ That means AD = 2 + 1 = 3 parts, and AP = \frac{2}{3} AD

∴ AP = \frac{2}{3} AD

∵ AD = 15 units

∴ AP = AP = \frac{2}{3} (15)

∴ AP = 10 units

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3 years ago
Can someone help me with this one please
Tom [10]

Do the same thing as the attached image.

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Find the value of the expressions 3x^3-2y^3-6x^2y^2+xy for x=2/3 and y=1/2
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Hi!

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Answer:

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Step-by-step explanation:

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