10% increase of $29,350?

Proving circles are similar: Choose any of the transformations that would be a step in proving that Circle A is similar to Circl

Ulleksa [173]

The transformations that would prove that circles A and C are similar are:

A. Reflect A over the line y=x
C. Dilate A by 3/2

<h3>How to prove that circle A and circle C are similar?</h3>

The circles are given as:

Circle A and B

Assume the following parameters:

The center of circle A is (2,3) with a radius of 2
The center of circle B is (3,2) with a radius of 3

To start with;

The circle A must be reflected across the line y = x with the following transformation rule:

(x,y) -> (y,x)

So, we have:

(2,3) -> (3,2)

Next, the radius of A must be dilated by 3/2 as follows:

New Radius = 3/2 * 2 = 3

After the transformations, we have the following parameters:

The center of circle A is (3,2) with a radius of 3
The center of circle B is (3,2) with a radius of 3

Notice that both circles now have the same center and radius.

Hence, both circles are similar

Read more about similar circles at:

brainly.com/question/9177979

7 0

2 years ago

Convert 3/18 to a decimal

frutty [35]

3/18 = 0.166667

hope this helps .

3 0

3 years ago

Read 2 more answers

In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time coll

algol13

Answer:

(a) The sample size required is 2401.

(b) The sample size required is 2377.

(c) Yes, on increasing the proportion value the sample size decreased.

Step-by-step explanation:

The confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE=z_{\alpha/2}\sqrt{\frac{\hatp(1-\hat p)}{n}}$

The information provided is:

MOE = 0.02

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

(a)

Assume that the proportion value is 0.50.

Compute the value of n as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\n=\frac{1.96^{2}\times0.50(1-0.50)}{0.02^{2}}\\=2401$

Thus, the sample size required is 2401.

(b)

Given that the proportion value is 0.55.

Compute the value of n as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.55(1-0.55)}{n}}\\n=\frac{1.96^{2}\times0.55(1-0.55)}{0.02^{2}}\\=2376.99\\\approx2377$

Thus, the sample size required is 2377.

(c)

On increasing the proportion value the sample size decreased.

8 0

4 years ago

Add this up (4k+1)+(3k+1)

aksik [14]

Answer:

7k + 2

Step-by-step explanation:

(4k + 1) + (3k + 1) =

4k + 3k + 1 + 1 =

7k + 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0

3 years ago

Read 2 more answers

Draw out a two column proof for each problem below. Complete all problems on one page and upload ONE photo of the entire assignm

Hunter-Best [27]

Two or more triangles are congruent if on comparison, they have equal lengths of sides, and measure of angles.

Therefore, the required proofs for each question are shown below:

Problem 1:

Congruent triangles are triangles with equal lengths of corresponding sides and measures of internal angles.

Thus,

STATEMENT REASON

1. <NMQ ≅ <NPQ Any point on a perpendicular bisector

makes equal measure of angle with the

two ends of the line segment.

2. NQ ⊥ MP Definition of a line.

3. MQ ≅ PQ Equal segments of a bisected line.

4. MN ≅ PN Any point on a perpendicular bisector

is at the same distance to the

two ends of the line segment.

5. <MNQ ≅ <PNQ Equal measure of the bisected angle.

Problem 2:

A line segment is the shortest distance between two points.

STATEMENTS REASONS

1. m<PSR ≅ m<PSQ A perpendicular bisector is always at a right

angle to the bisected line segment.

2. m<RPS ≅ m<QPS Equal measure of the bisected angle.

3. RS ≅ QS Property of a bisected line segment.

4. PR ≅ PQ Any point on a perpendicular bisector

is at the same distance to the two ends of

the line segment.

For more clarifications on the perpendicular bisector of a line segment, visit: brainly.com/question/12475568

#SPJ1

3 0

2 years ago