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Cloud [144]
4 years ago
12

WHY CAN'T ANYONE HELP ME PLEASE? THANKS! A student at a university makes money by buying and selling used cars. Charles bought a

used car and later sold it for a ​15% profit. If he sold it for ​$4669​, how much did Charles pay for the​ car?
Mathematics
1 answer:
rodikova [14]4 years ago
5 0

Step-by-step explanation:

<em>Given</em><em>, </em>

<em>a</em><em> </em><em>student</em><em> </em><em>(</em><em>Charles</em><em>)</em><em> </em><em>bought</em><em> </em><em>a</em><em> </em><em>car</em><em> </em><em>and</em><em> </em><em>sold</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>1</em><em>5</em><em> </em><em>%</em><em> </em><em>profit</em><em> </em><em>for</em><em> </em><em>$</em><em>4</em><em>6</em><em>6</em><em>9</em><em>.</em>

<em>we</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>formula</em><em>, </em>

<em>cp =  \frac{sp \times 100}{100 + p\%}</em>

<em>so</em><em>,</em><em> </em>

<em>cp =  \frac{4669 \times 100}{100 + 15}</em>

<em>by</em><em> </em><em>simplifying</em><em> </em><em>it we</em><em> </em><em>get</em><em>, </em>

<em>CP</em><em> </em><em>is</em><em> </em><em>$</em><em>4</em><em>0</em><em>6</em><em>0</em><em>.</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>cp</em><em> </em><em>was</em><em> </em><em>$</em><em>4</em><em>0</em><em>6</em><em>0</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Step-by-step explanation:

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Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure
Umnica [9.8K]

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

<u>Step(ii):-</u>

      \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

<u>Final answer</u>:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

7 0
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