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NARA [144]
3 years ago
15

Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo

r (g-h)(x) and (g+h)(x) and evaluate (g-h)(3). 2 o e m,曲 pe here to search
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find  (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5

and (g+h)(x) is given by

g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5

and (g-h)(3) is given by

-10(3)+5\\\\=-30+5\\\\=-25

Hence, our required values would be -10x+5, 2x+5 and -25.

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Answer:

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Step-by-step explanation:

OMG too difficult man!!

Thanks to my calculator to solve this hard question

5 0
2 years ago
Read 2 more answers
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
6/42 = n/7 N=?<br> I need to find what the numerator is.
PSYCHO15rus [73]
6/42 = n/7
Multiply by 7.
42/42 = n.
n = 1.
numerator = 42.
7 0
2 years ago
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3 years ago
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A 429 g piece of cheese costs $9.50. What will be the cost for 1.42 kg of this cheese?
stellarik [79]

The cost for 1.42 kg of this cheese will be $ 31.44 .

<h3>What does unit conversion entail?</h3>

The process of translating measurements of a given quantity between different units, frequently using multiplicative conversion factors that change the value of the measured quantity without changing its effects, is known as unit conversion. The specific circumstances and the desired result dictate the conversion process. This may be governed by a regulation, contract, set of technical requirements, or other publicly available standards.

<h3>Why is the unitary technique used? What is it?</h3>

In its simplest form, the unitary procedure is used to determine the value of a single unit from a given multiple.

How to calculate the value of one pen, for example, if 40 cost Rs. 400. To finish it, using the unitary method. Additionally, after the value of a single unit has been established, we can multiply that value by the quantity of additional units required to establish the value of the additional units. This is typically how the concepts of ratio and proportion are used. The unitary method entails calculating the value of a single unit before calculating the value of the required number of units.

Given that 0.429 kg of cheese cost $9.50

As a result, the price of 1 kg of cheese is $9.50/0.429, which is $ 22.14.

As a result, 1.42 kg of cheese will cost you $22.14 * 1.42 = $31.44.

To learn more about unit conversion, tap on the link below:
brainly.com/question/24587372

#SPJ10

5 0
1 year ago
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