All categories

3 years ago

What is the molar mass of AlCl3?

Chemistry

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

133.33 g/mole

Explanation:

To get the molar mass, you will need to first determine the atoms in the compound.

AlCl₃

We have aluminum (Al) and Chlorine (Cl)

Next step is to determine how many atoms of each element you have in the compound. The subscript will tell you how many. If you see no subscript, that means 1 atom.

Al = 1 atom

Cl = 3 atoms

Then you multiply the number of atoms by the atomic weight to get the molar mass of each element and add them up to get the total molar mass of the compound:

Element # of atoms atomic weight molar mass

Al 1 x 26.98 g/mole = 26.98 g/mole

Cl 3 x 35.45 g/mole = 106.35 g/mole

TOTAL = 133.33 g/mole

You might be interested in

Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o

Gnom [1K]

Answer: The empirical formula for the given compound is $C_5H_7N$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

$C_xH_yN_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of $CO_2=21.363mg=21.363\times 10^3g=21363g$

Mass of $H_2O=6.125g=6.125\times 10^3g=6125g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, $\frac{12}{44}\times 21363=5826.27g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, $\frac{2}{18}\times 6125=680.55$ of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = $\frac{485.52}{97.73}=4.96\approx 5$

For Hydrogen = $\frac{680.55}{97.73}=6.96\approx 7$

For Nitrogen = $\frac{97.73}{97.73}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is $C_5H_7N_1=C_5H_7N$

7 0

3 years ago

What is the difference between ionic compund and covalent compound

sleet_krkn [62]

A covalent bond is formed between two non-metals that have similar electronegativities.

An ionic bond is formed between a metal and a non-metal. Non-metals(-ve ion) are "stronger" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond.

5 0

3 years ago

How to do limiting reagents for chemistry?

gavmur [86]

Balance the chemical equation for the chemical reaction.
Convert the given information into moles.
Use stoichiometry for each individual reactant to find the mass of product produced.
The reactant that produces a lesser amount of product is the limiting reagent.
The reactant that produces a larger amount of product is the excess reagent.
To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.

4 0

3 years ago

In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch

LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of copper (II) chloride.

$M_2\text{ and }V_2$ are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

$M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?$

Putting values in above equation, we get:

$0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL$

Hence, the volume of stock solution needed are, 12.5 mL

8 0

3 years ago

A rule of thumb in baking is that 1/2 teaspoon of baking soda is neutralized by one cup of sour milk. the acid component in sour

Sophie [7]

Answer : The ionic equation will be:

$CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution.

When baking soda (sodium hydrogen carbonate) base react with lactic acid then it react to gives sodium lactate, carbon dioxide and water as a product.

The balanced chemical reaction will be:

$CH_3CH(OH)COOH(aq)+NaHCO_3(aq)\rightarrow CH_3CH(OH)COONa(aq)+H_2O(l)+CO_2(g)$

The ionic equation will be:

$CH_3CH(OH)COO^-(aq)+H^+(aq)+Na^+(aq)+HCO_3^-(aq)\rightarrow CH_3CH(OH)COO^-(aq)+Na^+(aq)+H_2O(l)+CO_2(g)$

3 0

3 years ago