Complete Question
How many moles of magnesium oxide are produced by the reaction of 1.82 g of magnesium nitride with 17.73 g of water? Mg3N2 + 3H20 + 2NH3 + 3MgO
Answer:
Explanation:
From the question we are told that:
Reaction Formula:
Therefore
Generally
Therefore
The given atom with 7 valence electrons is most likely to gain one more electron to achieve a full octet.
Given:
An atom with 7 valence electrons
To find:
Number electrons to achieve full octet by a given atom
Solution:
- The number of valence electrons in a given atom is 7.
- The number of valence electrons is 7 which means that the given atom will be a member of the halogen family.
- And as we know that halogen possesses one less electron to complete their octets. They by gaining one electron they achieve full octet and stability.
Similarly, the given atom with 7 valence electrons is most likely to gain one more electron to achieve a full octet.
Learn more about octet and valence electrons here:
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<h3><u>Answer;</u></h3>
0.002512 moles of H2O
<h3><u>Explanation</u>;</h3>
The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;
CH3COOH + NaOH ------> CH3COONa + H2O
Number of moles of CH3COOH = molarity × volume in litres
= 0.08 × 31.4/1000
= 2.512 × 10^-3
Similarly number of moles of NaOH = 1 × 24.3/1000
= 0.0243
From the reaction the mole ratio of CH3COOH : NaOH
Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512 moles, which is less than what is required.
Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.
Since; 1 mole of CH3COOH gives 1 mole of water.
Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O
Answer:
B. High levels of nitrogen and phosphorus from agricultural runoff, sewage, and industrial pollution were flowing into the bay.
Explanation:
I just did this question! <3
Answer:
TRIAL 1:
For “Event 0”, put 100 pennies in a large plastic or cardboard container.
For “Event 1”, shake the container 10 times. This represents a radioactive decay event.
Open the lid. Remove all the pennies that have turned up tails. Record the number removed.
Record the number of radioactive pennies remaining.
For “Event 2”, replace the lid and repeat steps 2 to 4.
Repeat for Events 3, 4, 5 … until no pennies remain in the container.
TRIAL 2:
Repeat Trial 1, starting anew with 100 pennies.
Calculate for each event the average number of radioactive pennies that remain after shaking.
Plot the average number of radioactive pennies after shaking vs. the Event Number. Start with Event 0, when all the pennies are radioactive. Estimate the half-life — the number of events required for half of the pennies to decay.
Explanation: