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gregori [183]
2 years ago
10

In a reaction that occurs in solution, the volume will not change. What happens to the concentration of the reactants? What happ

ens to the reaction rate as the reaction proceeds?
(will give brainllest)
Chemistry
1 answer:
Stella [2.4K]2 years ago
6 0

Answer:

the reaction will increase

Explanation:

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The importance of the Galapagos to Darwin theory is chances  Darwin discovered several species of finches that varied from island to island .
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which are 12 <span>species ,also the Darwin theory is  only gradually accepted because people don't believe in them today</span>
3 0
2 years ago
Which of the following processes are physical changes? Mark all
stich3 [128]

The process that is physical changes is:

  • mixing frozen orange juice concentrate with water

<h3>What is a physical change?</h3>

A physical change can be described as a type of  change  that take place in physical without chemical reaction as opposed to chemical change.

They are changes that are  usually reversible it should be noted that physical change do not  involve the alterations  as regards the  chemical make up of a particular  substance  and as a result of this , in physical change, there is   no formation of new product.

Therefore, The process that is physical changes is mixing frozen orange juice concentrate with water

Read more about physical changes here:

brainly.com/question/13056570

#SPJ1

7 0
1 year ago
White vitriol molecular formula<br>and green vitriol molecular formula??​
IgorC [24]

Answer:

<em>Green</em><em> </em><em>vitriol</em><em>-</em><em> </em><em>FeSO4·7H2O</em>

<em>white</em><em> </em><em>vitriol</em><em>-</em><em> </em><em>ZnSO₄</em>

8 0
2 years ago
I need your help!! about Chemistry (15 point!!)
irakobra [83]
1. I think it is true?
2. Low melting points
3. True
4. Atomic number, I think it’s periods?
5. Groups?


Sorry, I might not get all of them right :(


Hope this helps you in any way!!
6 0
2 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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