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Ronch [10]
3 years ago
12

Which of the following alkyl halides will react fastest with CH3OH in an SN1 mechanism?

Chemistry
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

IV

Explanation:

The complete question is shown in the image attached.

Let us call to mind the fact  that the SN1 mechanism involves the formation of carbocation in the rate determining step. The order of stability of cabocations is; tertiary > secondary > primary > methyl.

Hence, a tertiary alkyl halide is more likely to undergo nucleophilic substitution reaction by SN1 mechanism since it forms a more stable cabocation in the rate determining step.

Structure IV is a tertiary alkyl halide, hence it is more likely to undergo nucleophilic  substitution reaction by SN1 mechanism.

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A volume of 80.0 mL of aqueous potassium hydroxide (KOH) is titrated against a standard solution of sulfuric acid (H2SO4). What
yaroslaw [1]

Answer:

0.478 M

Explanation:

Let's consider the neutralization reaction between KOH and H₂SO₄.

2 KOH + H₂SO₄ → K₂SO₄ + 2 H₂O

12.7 mL of 1.50 M H₂SO₄ react. The reacting moles of H₂SO₄ are:

0.0127 L × 1.50 mol/L = 0.0191 mol

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of KOH are 2 × 0.0191 mol = 0.0382 mol

0.0382 moles of KOH are in 80.0 mL. The molarity of KOH is:

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24. Which of the following pairs of solutions produce a precipitate when combined? A) Fe(NO); and KCI B) NH4Cl and AgNO3 C) KOH
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2 years ago
The equation 2C3H7OH + 9O2 yield 6 CO2 + 8H2O is an example of what type of reaction
Furkat [3]
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What is the mass percent of oxygen in sodium bicarbonate (NaHCO3)?
Alenkasestr [34]
The answer is 57.14%.

First we need to calculate molar mass of <span>NaHCO3. Molar mass is mass of 1 mole of a substance. It is the sum of relative atomic masses, which are masses of atoms of the elements.

Relative atomic mass of Na is 22.99 g
</span><span>Relative atomic mass of H is 1 g
</span><span>Relative atomic mass of C is 12.01 g
</span><span>Relative atomic mass of O is 16 g.
</span>
Molar mass of <span>NaHCO3 is:
22.99 g + 1 g + 12.01 g + 3 </span>· <span>16 g = 84 g

Now, mass of oxygen in </span><span>NaHCO3 is:
3 </span>· 16 g = 48 g

mass percent of oxygen in <span>NaHCO3:
48 g </span>÷ 84 g · 100% = 57.14%

Therefore, <span>the mass percent of oxygen in sodium bicarbonate is 57.14%.</span>
8 0
3 years ago
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