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REY [17]
3 years ago
11

-Example of an element that has an electron distribution ending in s2p1?

Chemistry
1 answer:
nataly862011 [7]3 years ago
4 0
Example of an element that has an electron distribution ending in s2p1 is Na or sodium. The complete electron configuration of Na 1s22s22p63s<span>1. </span>Example of an element that has an electron distribution ending in s2d2 is Ca or calcium. The complete electron configuration of Ca is 1s22s22p63s23p64s2.
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Convert 6 grams of carbon atoms into miles
anyanavicka [17]
How many grams Carbon in 1 moles? The answer is 12.0107.
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molecular weight of Carbon<span> or </span>moles
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<span>The SI base unit for </span>amount of substance<span> is the mole.</span>
1 grams Carbon is equal to 0.0832590939745 mole.
Note that rounding errors may occur, so always check the results.
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4 0
2 years ago
Calorimeter containing 1000 grans of water the initial temperature of water is 24.85 degrees . the heat of water is 4.184 j/g de
kvasek [131]
<h3><u>Answer;</u></h3>

10.80 ° C

<h3><u>Explanation;</u></h3>

From the information given;

Initial temperature of water =  24.85°C

Final temperature of water = 35.65°C

Mass of water = 1000 g

The specific heat of water ,c = 4.184 J/g °C.

The heat capacity of the calorimeter  = 695 J/ °C

Change in temperature ΔT = 35.65°C - 24.85°C

                                             = 10.80°C

3 0
3 years ago
Which element decreases its oxidation number in this reaction? bicl2 + na2so4 → 2nacl + biso4?
kifflom [539]
The balanced reaction is as follows;
BiCl₂ + Na₂SO₄ --> 2NaCl + BiSO₄
this is a double displacement reaction 
the oxidation number of Bi is +2 in both BiCl₂ and BiSO₄
oxidation number of Cl is -1 in both BiCl₂ and NaCl 
oxidation number of Na is +1 in both Na₂SO₄ and NaCl
oxidation numbers of elements in SO₄²⁻ remains the same in both compounds.Therefore the oxidation state in any of the elements in the reaction doesn't change. Neither of the elements show an increase or decrease in the oxidation numbers .
Answer for this question is no element decreases its oxidation number.

5 0
3 years ago
Read 2 more answers
Help please!! I'll name you brainliest!!
Inessa05 [86]

the answers is cacih2

wjdgagqjdhdgahahdhvddvvsvshsd

7 0
3 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
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