Mode are repeating numbers in a sequence therefore 23 is your mode
Based on Janice average, she spent $50 at the last store.
Let a, b, c, d, e represent the money spent on the five stores respectively.
Since she spent an average of $30 at each store, hence:
(a + b + c + d + e) / 5 = 30
(a + b + c + d + e) = 150
She spent $100 on the first four stores, hence:
a + b + c + d = 100
(a + b + c + d + e) = 150
100 + e = 150
e = 50
Hence based on Janice average, she spent $50 at the last store.
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Answer: Yes, I believe that she does, because 15 is greater than 13.
Step-by-step explanation:
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
Answer:a2=5 , a1=1 , a0=3, a5=2 , a4=5 , a3=2 , a6=0 , a10=5 , a9=3 , a8=8 , a7=2
Step-by-step explanation:
63 x 45=2835
