The length of a square is 5/6 foot. What is the area of the square?

kimmys savings account has a balance of $76.23 in june.by september, her balance is 5 times as much as her june balance.between

nalin [4]

From the information you have given me, I would say Kimmy has $<span>468.98 </span>dollars in her bank account.

Does she get more money during the other months, just as she had gotten 5 times as much as she had in a 3 month span? (From june to september.) All I could tell was her money was multiplied by 5, then you add $87.83 more into her account.

Please check my math if you want to be sure.
$76.23 * 5 = $381.15
$381.15 + 87.83 = 468.98

4 0

3 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

How much water will be needed to completely fill a rectangular tank that has a length of 3 meters a width of 3 meters

IgorC [24]

Answer:

A

Step-by-step explanation:

because when you multiply 3x3 (the base) times 18(the height) you get= 162

8 0

3 years ago

Please help !!!!!!!!!

vodka [1.7K]

Answer:

A= 41° a=9.84... b=11.32...

Step-by-step explanation:

given B = 49° and C = 90°

and A + B + C = 180

so 49+90+A=180

A= 41°

we also know c (small) is 15 units

and maybe you know this SOH CAH TOA? no, i'm not calling anyone names :P this is just the mnemonic to memorize how sin , cos and tan fit sin(Ф)=Opp/Hyp Cos(Ф)=Adj/Hyp Tan(Ф)=Opp/Adj

Hyp is the hypontenuse of the triangle ( the long side). Opposite (Opp) means the side opposite from what ever angle you are starting at..adjacent (Adj) means what ever angle is next to where you are starting from.

use Cos(49) to find the side a

a is an adjacent side to the 49 angle. We know the Cos and we know the Hyp .. so solve for adj...

Cos(Ф)=Adj/ Hyp

Hyp*Cos(Ф)=Adj

15*Cos(49)= Adj

9.84...=Adj=a

now lets' use sin for the opposite side or b

sin(Ф)=Opp/Hyp

Hyp*Sin(Ф) = Opp

15*sin(49)= Opp

11.32...= Opp =b

7 0

3 years ago

Please help due in 10 mins

USPshnik [31]

Answer:

the answers is -4 for this exerxises

6 0

2 years ago