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Nadya [2.5K]
3 years ago
5

Any help is appreciated:)God blast it the photo didn’t load

Mathematics
1 answer:
mart [117]3 years ago
6 0

... what is the question lol

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Velma needs to crate 59 watermelons. If she can fit 7 watermelons in each crate, how many crates does she need?
Mademuasel [1]

Answer:

The answer would be nine

Explanation:

59 divided by 7 is 8 with 3 remaning but all must be included so you have anothr crate for the remaining the and sice 8+1=9. Velma needs 9 crates. Hope this Helps!!

5 0
3 years ago
Solve pls brainliest
Goshia [24]

Hey there!

39 = - u / 6

MULTIPLY 6 to BOTH SIDES

39(9) = (-u / 6)(6)

CANCEL out: the RIGHT side

KEEP: the LEFT side because it helps solve for the u-value

NEW EQUATION: -u = 234

DIVIDE -1 to BOTH SIDES

-1u / -1 = 234 / -1

CANCEL out: -1 / -1 because it gives you 1

KEEP: 234 / -1 because it gives you the result of the u-value

NEW EQUATION: u = 234 / -1

SIMPLIFY IT!

u = -234

Therefore, your answer is: [u = -234]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0
3 years ago
Read 2 more answers
What is 3.84 ÷ 0.96?
Ronch [10]
I believe the answer is 4
7 0
3 years ago
Read 2 more answers
There are 26 prize tickets in a bowl,labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen,not
labwork [276]

Answer:

3.1%, dependent event

Step-by-step explanation:

We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:

5/26

since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:

4/25

Therefore the final probability is:

5/26 * (4/25) = 0.031

In other words, selecting a vowel and then another (without replacement) the probability is 3.1%

The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.

5 0
3 years ago
Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.
meriva

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}

\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}

5 0
3 years ago
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