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3 years ago

The heat of a reaction may be found with the equation q=mcΔT.

Chemistry

1 answer:

sweet-ann [11.9K]3 years ago

4 0

Answer:

B) -1551 kJ

Explanation:

There are two heat flows in this question.

Heat released by engine + heat absorbed by water = 0

q₁ + q₂ = 0

q₁ + mCΔT = 0

Data:

m = 2.51 kg

C = 3.41 J°C⁻¹g⁻¹

T_i = 23.8 °C

T_f =205 °C

Calculations:

(a) ΔT

ΔT = 205 °C - 23.8 °C = 181.2 °C

(b) q₂

q₂ = mCΔT = 2510 g × 3.41 J·°C⁻¹g⁻¹ × 181.2 °C = 1.551× 10⁶ J = 1551 kJ

(c) q₁

q₁ + 1551 kJ = 0

q₁ = -1551 kJ

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a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $0.80M^{-1}s^{-1}$

t = time taken = 95 s

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Now put all the given values in above equation, we get:

$0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)$

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

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3 years ago

Bromine, a liquid at room temperature has a boiling point of 58 degrees celsius and a melting point at -7.2 degree celsius bromi

ra1l [238]

Hello!

Bromine can be classified as a pure substance.

Why?

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4 years ago

Compare molecular & covalent network crystal solid?

Daniel [21]

Answer:

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2 years ago

Explain how copper conducts electricity?

gladu [14]

Answer:

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Explanation:

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3 years ago

SHOW YOUR WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

WARRIOR [948]

Answer:

1.375%

Explanation:

Percent Error = measured value - accepted value/ accepted value x 100

Measured Value: 15.78

Accepted Value: 16.00

Work:

$\frac{15.78-16.00}{16.00}$ * 100

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3 years ago