C₆H₆ + 3H₂ → C₆H₁₂
Benzene + 3 molecules of hydrogen = cyclohexane
So essentially what happens is that benzene contains three double bonds and when reacted with hydrogen then these three double bonds can be broken and the hydrogen bond to the tetravalent carbon to restore its for bonds forming cyclohexane
Answer:
3.97 M
Explanation:
Given data:
Initial volume V₁ = 318 mL
Initial molarity M₁ = 5.75 M
New volume V₂= 461 mL
New concentration M₂= ?
Solution:
New volume V₂= 143 mL+ 318 mL
New volume V₂= 461 mL
Formula:
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
M₂ = 5.75 M × 318 mL / 461 mL
M₂ = 1828.5 M. mL/ 461 mL
M₂ = 3.97 M
Answer:
2,54x10² mmHg
Explanation:
To solve this problem you can use Clausius-Clapeyron equation that serves to estimate vapor pressures or temperatures:

Where:
P1 is 1,00x10² mmHg
ΔHvap is 39,3 kJ/mol
R is gas constant 8,314x10⁻³ kJmol⁻¹K⁻¹
T1 is 34,90°C + 273,15 = 308,05 K
T2 is 54,81°C + 273,15 = 327,96 K
Thus:

Thus, P2 is <em>2,54x10² mmHg</em>
I hope it helps!
Answer:
V1= 150ml
Explanation:
C1= 1.25, V1=?, C2= 0.75, V2= 250ml
Applying dilution formula
C1V1= C2V2
V1= (0.75×250)/1.25 = 150ml