Answer:
1: At temperatures below 542.55 K
2: At temperatures above 660 K
Explanation:
Hello there!
In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:
![\Delta G=\Delta H-T\Delta S](https://tex.z-dn.net/?f=%5CDelta%20G%3D%5CDelta%20H-T%5CDelta%20S)
Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:
1:
![0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K](https://tex.z-dn.net/?f=0%3D%5CDelta%20H-T%5CDelta%20S%5C%5C%5C%5CT%3D%5Cfrac%7B-102kJ%2Fmol%7D%7B-0.188kJ%2Fmol-K%7D%20%5C%5C%5C%5CT%3D542.55K)
It means that at temperatures lower than 542.55 K the reaction will be spontaneous.
2:
![0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K](https://tex.z-dn.net/?f=0%3D%5CDelta%20H-T%5CDelta%20S%5C%5C%5C%5CT%3D%5Cfrac%7B132kJ%2Fmol%7D%7B0.200kJ%2Fmol-K%7D%20%5C%5C%5C%5CT%3D660K)
It means that at temperatures higher than 660 K the reaction will be spontaneous.
Best regards!
Answer:
Explanation:
Efficiency of the electric power plant is ![e=1-\frac{T_{2}}{T_{1}}](https://tex.z-dn.net/?f=e%3D1-%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D)
Here Temperature of hot source ![T_{1} = 450^{o}C=450+273=723 K](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%20450%5E%7Bo%7DC%3D450%2B273%3D723%20K)
and Temperature of sink ![T_{1} = 20^{o}C=20+273=293 K](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%2020%5E%7Bo%7DC%3D20%2B273%3D293%20K)
Hence the efficiency is
Now another formula for thermal efficiency Is
![e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}](https://tex.z-dn.net/?f=e_%7Btherm%7D%3D%5Cfrac%7BQ_%7B1%7D-Q_%7B2%7D%7D%7BQ_%7B1%7D%7D%3D%5Cfrac%7BW%7D%7BQ_%7B1%7D%7D)
Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found
W is the of work done and W = QI -Q2
Hence From![e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}](https://tex.z-dn.net/?f=e_%7Btherm%7D%3D%5Cfrac%7BQ_%7B1%7D-Q_%7B2%7D%7D%7BQ_%7B1%7D%7D%3D%5Cfrac%7BW%7D%7BQ_%7B1%7D%7D)
![W=e(Q_{1})=(0.5947)(100)=59.47MJ](https://tex.z-dn.net/?f=W%3De%28Q_%7B1%7D%29%3D%280.5947%29%28100%29%3D59.47MJ)
Hence the of heat transferred to the river Is ![Q_{2} -W = (100 -59.47=40.53](https://tex.z-dn.net/?f=Q_%7B2%7D%20-W%20%3D%20%28100%20-59.47%3D40.53)
Maybe because gravity has control of each formation of the solarsydtem thats why its just a guess
Answer:
Answer is D.it gains and loses electrons.
Explanation:
I hope it's helpful!