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3 years ago

In the following diagram, BC is parallel to DE 30 POINTS

Mathematics

2 answers:

babymother [125]3 years ago

8 0

Answer:

∠x = $29^{0}$

Step-by-step explanation:

Since /BC/ ll /DE/, then ∠CBA = ∠DAB (alternate angles)

Thus,

∠DAB + $109^{0}$ + x = $180^{0}$ (sum of angles on a straight line)

⇒ $42^{0}$ + $109^{0}$ + x = $180^{0}$

$151^{0}$ + x = $180^{0}$

make 'x' the subject of the formula,

x = $180^{0}$ - $151^{0}$

∴ x = $29^{0}$

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

Step-by-step explanation:

In parallel lines, allied angles have a sum of 180.

Therefore, angle CBD + angle EAB = 180

Therefore, 42 + 109 + x = 180

x + 151 = 180

x = 29

Hope it helps and if it does, please mark me brainliest...

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How do you solve: you have two distinct gaseous compounds made from element x and y. the mass percents are as follows: compound

saveliy_v [14]

solution:

Let's assume that a unit of compound 1 is 100g and a unit of compound 2 is 100g... in other words, compound 1 will be 30.43g X and 69.57g Y, and compound 2 will be 63.64g X and 36g Y.

According to the given in your problem, we can also write the following two chemical equations:

X+2Y--> 2(compound 1)

2X+Y--> 2(compound 2)

using the 100g units above we can also write this as:

X+2Y--> 2(30.43g X) + 2(69.57g Y)

2X+Y--> 2(63.64g X) + 2(36g Y)

We add these two chemical equations together and get:

3X+3Y--> 2(30.43g+63.64g X) + 2(69.57g+36g Y)

This can be written more simply as:

3X+3Y--> 188.14g X + 211.14g Y

In other words, 3 volumes of X gives 188.14g of X, and 3 volumes of Y gives 211.14g of Y. Dividing one by 3 and you get 62.71g per volume X, and 70.38g per volume Y.

x: 62.71 g/mol.

Y: 70.38 g/mol.

8 0

2 years ago

Find the width of a rectangle with perimeter 92 and length 19

lora16 [44]

Answer:

Step-by-step explanation:

perimeter = l + b + l + b or 2(l + b)

92 = 19 + 19 + 2b

92 = 38 + 2b

2b = 92 - 38