Question

In the following diagram, BC is parallel to DE 30 POINTS

Answer 1

Answer:

∠x = $29^{0}$

Step-by-step explanation:

Since /BC/ ll /DE/, then ∠CBA = ∠DAB  (alternate angles)

Thus,

       ∠DAB + $109^{0}$ + x = $180^{0}$ (sum of angles on a straight line)

 ⇒      $42^{0}$ + $109^{0}$ + x =  $180^{0}$

          $151^{0}$ + x = $180^{0}$

make 'x' the subject of the formula,

       x = $180^{0}$ - $151^{0}$

∴     x   = $29^{0}$

Answer 2

Answer:

29

Step-by-step explanation:

In parallel lines, allied angles have a sum of 180.

Therefore, angle CBD + angle EAB = 180

Therefore, 42 + 109 + x = 180

x + 151 = 180

x          = 29

Hope it helps and if it does, please mark me brainliest...