In the case above, what just comes to mind as part of the process is option d.
<h3>What is sniffer?</h3>
A sniffer is known to be a kind of a software or hardware tool that gives room for a person to be able to “sniff” or look through one's internet traffic in real time, getting all the data flowing to and from a person's computer.
Therefore, In the case above, what just comes to mind as part of the process is option d.
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Answer:
Let the two string type variables be var1 and var2. The value stored in these two variables is : The "use" of quotations causes difficulties.
- The variable which uses quoted string:
string var1 = "The \"use\" of quotations causes difficulties.";
- The variable which does not use quoted string:
string var2 = "The " + '\u0022' + "use" + '\u0022' + " of quotations causes difficulties.";
- Another way of assigning this value to the variable without using quoted string is to define a constant for the quotation marks:
const string quotation_mark = "\"";
string var2 = "The " + quotation_mark + "use" + quotation_mark + " of quotations causes difficulties.";
Explanation:
In order to print and view the output of the above statements WriteLine() method of the Console class can be used.
Console.WriteLine(var1);
Console.WriteLine(var2);
In the first statement escape sequence \" is used in order to print: The "use" of quotations causes difficulties. This escape sequence is used to insert two quotation marks in the string like that used in the beginning and end of the word use.
In the second statement '\u0022' is used as an alternative to the quoted string which is the Unicode character used for a quotation mark.
In the third statement a constant named quotation_mark is defined for quotation mark and is then used at each side of the use word to display it in double quotations in the output.
The voltage on a resistor will be "12 V".
According to the given question,
Current,
Power,
As we know the formula,
→ 
or,
→ 
By putting the giving values, we get
→ 
→ 
Thus the solution above is right.
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Answer:
Non-Payload Bytes sent are 1476(total) - 393 (payload) = 1083 bytes
1083 (non-payload) out of 1476(total) is 73.37 %
Non-Hello bytes sent are 1476(total) - 53(hello payload) = 1425 bytes
1425(non-hello) out of 1476(total) is 96.54 %
?? What does that mean? What is the question