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3 years ago

What steps can you take to secure your private information?.

Computers and Technology

1 answer:

pogonyaev3 years ago

6 0

Answer:

Below:

Explanation:

1. Practice mail security. Use a public mailbox rather than your home mailbox to send bill payments and other mail containing sensitive information. Pick your mail up promptly and ask the post office to hold it while you’re away.

2. Guard your Social Security number. Don’t carry your Social Security card, military ID, Medicare, or other cards that have your Social Security number on them unless you are going somewhere where you will need them. Only provide your Social Security number when there is a legitimate need to do so.

3. Lock and shred. Keep your billing and banking statements and other personal records locked up and shred them when no longer needed.

4. Stop prescreened credit and insurance mailings. Call toll-free 1-888-567-8688 to get off mailing lists for credit and insurance offers. Your Social Security number will be required. This keeps thieves from intercepting and accepting the offers in your name and doesn’t affect your eligibility for credit or insurance.

5. Keep private information to yourself. Never respond to phone calls or emails asking to confirm your Social Security number or account numbers. Don’t leave PIN numbers, passwords or other personal information around for others to see.

6. Be safe online. Use anti-virus and anti-spyware software and a firewall on your computer and keep them updated. When you provide financial or other sensitive information online, the address should change from “http” to “https” or “shttp.” A symbol such as a lock that closes may also indicate that the transmission is secure.

7. Look at your bills and bank statements promptly. If you find any charges or debits that you never made, contact the bank or company immediately.

Hope it helps.......

It's Muska...

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3 years ago

write an application to presell a limited number of cinema tickets. each buyer can buy as many as 4 tickets. No more than 100 ti

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Answer:

The program for this question can be given as:

Program:

import java.util.*; //import package

public class TicketSeller //define class

{

public static void main(String ar[]) //main method

{

int totalTickets=100,userCount=0,remainingTickets=100,numTickets; // varaibale

try //try block

{

Scanner ob= new Scanner(System.in); //input by user

System.out.println("Total Tickets:"+totalTickets);

while(remainingTickets!=0) //loop

{

System.out.print("Enter no of Tickets to buy:"); //message.

numTickets=ob.nextInt(); //taking input

if(numTickets<=4) //conditional statements.

{

if(remainingTickets>=numTickets)

{

remainingTickets=remainingTickets-numTickets; //calculate remainingTickets

userCount++;

System.out.println("remaining tickets : "+remainingTickets+" user :"+userCount);

}

else

{

System.out.println("Invalid Input");

}

else

{

System.out.println("Invalid Input");

}

catch(Exception e) //catch block.

{

}

Output:

Total tickets:100

Enter no of Tickets to buy: 4

Remaining tickets : 96 User :1

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Remaining tickets : 92 User :2

Enter no of Tickets to buy: 4

Remaining tickets : 88 User :3

Enter no of Tickets to buy: 4

Remaining tickets : 0 User :25

Explanation:

In the above Program firstly we import the package for the user input. Then we declare the class that is (TicketSeller) given in question. In this class we declare the main method in the main method we declare the variable that is totalTickets, userCount, remainingTickets and numTickets .Then we use the exception handling. we use this for providing the validation from the user side that users don't insert value less the 4. In the exception handling, we use the multiple catch block with try block. Then we input from the user and calculate the values and in the last, we print all the values.

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3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

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Answer:

The smallest number of servers required is 3 servers

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Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

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Read 2 more answers