Answer:
The answer is B!!
Step-by-step explanation:
What do we know given from the statement above the photo? We are told <Q is congruent to <S, and QR is congruent to SR. So by given that, we have an angle (angle Q or angle S), a side (side QR or SR), and another angle (angle R), so we have ASA. I hope this helps!!
Answer:
<h3>★ <u>11/30</u> is the right answer. ★</h3>
Step-by-step explanation:
- Number of male students who got 'A' in the test is 11
- Number of female students who got 'A' in the test is 19
- Total students who got 'A' in the test is 30
- Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/30</u></em>
Explanation:
First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

Note that both sine and cosine are negative because x is in the 3rd quadrant.
Recall the addition identities listed below:









Therefore, the expression reduces to



1. False because a rational is a fraction or part of a number (

).

2. True; a real number is any number that isn't imaginary (

)
3. True; same reason
4. True; an integer is any number that can be wrote without a fraction or decimal (the opposite of rational).
5. True;

and that's a decimal.
6. True; the natural number system starts from 0 and counts upwards
7. True; reason above
Answer:
all real numbers
Step-by-step explanation:
Here is the solution to the first inequality:
3(2x +1) > 21 . . . . . . given
6x +3 > 21 . . . . . . . . eliminate parentheses
6x > 18 . . . . . . . . . . .subtract 3
x > 3 . . . . . . . . . . . . divide by 6
This is all numbers to the right of 3 on the number line.
__
The solution to the second inequality is ...
4x +3 < 3x + 7 . . . . given
x < 4 . . . . . . . . . . . . subtract 3x+3
This is all numbers to the left of 4 on the number line.
__
The conjunction in the system of inequalities is "or", so we are looking for values of x that will satisfy at least one of the conditions. <em>Any value of x</em> will satisfy one or the other or both of these inequalities. The solution is all real numbers.