Answer:
μ= 65 inches; σ= 0.625 inch
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
By the central limit theorem, the sample of 16 will have:
So the correct answer is:
μ= 65 inches; σ= 0.625 inch
The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
The answer is Angle T = angle N
9x^2-49
It equals:
<span>(<span><span>3x</span>+7</span>)</span><span>(<span><span>3x</span>−7</span><span>)
Hope this helps!
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Answer:
16.16.16
Step-by-step explanation:
please let me know if I'm wrong
but I learned that you don't do 4×2 you have to multiply 4 twice by itself so it would be 16 because 4×4=16
