Question

How many milliliters of syrup are in a 100-ml sample containing 6.55 g of syrup per 20 mL if the syrup's specific gravity is 1.31?

Answer 1

Answer:

25 milliliters

Step-by-step explanation:

Given:

volume of sample = 100 ml

Syrup present in sample = 6.55 g per 20 mL

Therefore in 100 mL, amount of syrup present = $\frac{\textup{6.55}}{\textup{20}}\times100$

or

amount of syrup present in 100 mL sample = 32.75 grams

Now,

Specific gravity of the syrup = 1.31

also,

Specific gravity of the syrup = $\frac{\textup{Density of syrup}}{\textup{Density of water}}$

or

1.31 = $\frac{\textup{Density of syrup}}{\textup{1 g/mL}}$

or

Density of syrup = 1.31 g/mL

also,

Density = $\frac{\textup{Mass}}{\textup{Volume}}$

therefore,

1.31 = $\frac{\textup{32.75}}{\textup{Volume of syrup in the sample}}$

or

Volume of syrup in the sample = $\frac{\textup{32.75}}{\textup{1.31}}$

or

Volume of syrup in the sample = 25 milliliters