Answer:
Heat Capacity of calorimeter is 6.842 kJ/°C
Explanation:
4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)
ΔH°rxn = -1.28 x 10⁴ kJ
4 moles of aniline gives 12800 kJ of heat,
1 mole of aniline will give 12800/4 kJ amount of heat = 3200 kJ
ΔH°rxn for 1 mole of aniline = -3200 kJ
1 mole of aniline weighs 93.13 g/mol
6.55 g of aniline has 6.55/93.13 moles = 0.0703 moles
And this would give off 0.0703 × 3200J amount of heat off
0.0703 × 3200 = 225.1 kJ.
Heat lost by aniline = Heat gained by calorimeter,
Heat lost by aniline = 225.1 kJ
Heat gained by calorimeter = C ΔT = C (32.9)
225.1 = C (32.9)
C = 6.842 kJ/°C
