Question

A 6.55 g sample of aniline (C_{6}H_{5}H_{2}, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter.

Answer 1

Answer:

Heat Capacity of calorimeter is 6.842 kJ/°C

Explanation:

4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)

ΔH°rxn = -1.28 x 10⁴ kJ

4 moles of aniline gives 12800 kJ of heat,

1 mole of aniline will give 12800/4 kJ amount of heat = 3200 kJ

ΔH°rxn for 1 mole of aniline = -3200 kJ

1 mole of aniline weighs 93.13 g/mol

6.55 g of aniline has 6.55/93.13 moles = 0.0703 moles

And this would give off 0.0703 × 3200J amount of heat off

0.0703 × 3200 = 225.1 kJ.

Heat lost by aniline = Heat gained by calorimeter,

Heat lost by aniline = 225.1 kJ

Heat gained by calorimeter = C ΔT = C (32.9)

225.1 = C (32.9)

C = 6.842 kJ/°C

Answer 2

Answer:

Explanation:

The answer is in the attachment