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Vladimir79 [104]
3 years ago
8

The charge on the most stable ion of zinc​

Chemistry
1 answer:
Natalija [7]3 years ago
8 0
Zinc (Zn) always has a +2 charge. It is one of the exceptions.
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A water treatment tablet contains 20.0 mg of tetraglycine hydroperiodide, 40.0% of which is available as soluble iodine. If two
Galina-37 [17]

Answer:

16\ \text{ppm}

Explanation:

Mass of one tablet = 20 mg

Mass of two tablets = 2\times 20=40\ \text{mg}

Percent that is soluble in water = 40%

Mass of tablet that is soluble in water = 0.4\times 40=16\ \text{mg}

So, mass of solute is 16\ \text{mg}

Density of water = 1 kg/L

Volume of water = 1 L

So, mass of 1 L of water is 1\times 1=1\ \text{kg}=1000\ \text{g}

PPM is given by

\dfrac{\text{Mass of solute}}{\text{Mass of solvent}}\times 10^6=\dfrac{16\times 10^{-3}}{1000}\times 10^6\\ =16\ \text{ppm}

Hence, the concentration of iodine in the treated water 16\ \text{ppm}.

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Which of the following represents a beta particle?
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A chemical test has determined the concentration of a solution of an unknown substance to be 2.41 M. a 100.0 mL volume of the so
Oksana_A [137]

Answer : The molar mass of unknown substance is, 39.7 g/mol

Explanation : Given,

Mass of unknown substance = 9.56 g

Volume of solution = 100.0 mL

Molarity = 2.41 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

2.41M=\frac{9.56g\times 1000}{\text{Molar mass of unknown substance}\times 100.0mL}

\text{Molar mass of unknown substance}=39.7g/mol

Therefore, the molar mass of unknown substance is, 39.7 g/mol

5 0
3 years ago
when carbon dioxide is bubbled through lime water the solution first turn milky and to colour less . Explain why these changes o
Annette [7]

Answer:

When excess of carbon dioxide is passed in lime water, calcium carbonate is converted to calcium bicarbonate which is soluble, hence the milkiness due to calcium carbonate disappears.

Explanation:

Ca(OH)2+CO2 → CaCO3 (Milkiness) ↓+H2O

CaCO3+H2O+CO2 → Ca(HCO3)2 (soluble)

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