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Olenka [21]
3 years ago
10

1. Mountains are most likely formed

Chemistry
1 answer:
Darya [45]3 years ago
4 0
The correct answer is D
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What is the difference between boiling point and normal boiling point?​
Softa [21]

Answer:

The boiling point is the temperature at which the vapor pressure equals the pressure of gas.

The normal boiling point is the temperature at which the vapor pressure equals one atmosphere

Explanation:

5 0
3 years ago
What does the mass number of an atom represent?.
mamaluj [8]

Answer:

the sum of the numbers of protons and neutrons present in the nucleus of an atom.

8 0
2 years ago
What specific electrophile does benzene attack when it undergoes nitration??
Deffense [45]
<span><span>The reaction is as follows:
        C6H6   </span>+   HNO3   +      H2SO4     ------------> </span>C6H5NO2<span>   +   H</span>2<span>O
(BENZENE) (NITRIC ACID)(CATALYST)
</span>NO2(+) is the electrophile that acctacks on the benzene ring in nitration process.
7 0
3 years ago
Calculate the standard potential for the following galvanic cell: Ni(s) | Ni2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
mylen [45]

Answer:

1.06  V  

Explanation:

The standard reduction potentials are:

Ag^+/Ag     E° =  0.7996 V  

Ni^2+/Ni     E° = -0.257   V

The half-cell and cell reactions for Ni | Ni^2+ || Ag^+ | Ag are

Ni → Ni^2+ + 2e-                     E° = 0.257   V

<u>2Ag^+ 2e- → 2Ag               </u>    <u>E° = 0.7996 V </u>

Ni + 2Ag^+ → Ni^2+ + 2Ag     E° = 1.0566  V

To three significant figures, the standard potential for the cell is 1.06 V .

8 0
3 years ago
A sample of oxygen gas is compressed from 30.6 L to 1.8 L at constant temperature pressure of 1.8 atm. Calculate the amount of e
ad-work [718]

Answer:

the change in the internal energy of the system is 3,752.67 J

Explanation:

Given;

initial volume of the gas, V₁ = 30.6 L

final volume of the gas, V₂ = 1.8 L

constant pressure of the gas, P = 1.8 atm

Energy released by the system, Q = 1.5 kJ = 1,500 J

Apply pressure-volume work equation, to determine the work done on the gas;

w = -PΔV

w = -P(V₂ - V₁)

w = - 1.8 atm(1.8 L - 30.6 L)

w = 51.84 L.atm

w = 51.84 L.atm x 101.325 J/L.atm

w = 5,252.67 J

The change in the internal energy of the system is calculated as;

ΔU = Q + w

Since the heat is given out, Q = - 1,500 J

ΔU = -1,500 J  +  5,252.67 J

ΔU = 3,752.67 J

Therefore, the change in the internal energy of the system is 3,752.67 J

3 0
3 years ago
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