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qaws [65]
3 years ago
5

If the density of a 45.0 cm3 block of wood is 0.65 g/ml what is the mass of the wood?

Chemistry
1 answer:
wlad13 [49]3 years ago
5 0

Answer:

\boxed {\tt mass=29.25 \ grams}

Explanation:

The density formula is mass over volume.

d=\frac{m}{v}

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

d*v=\frac{m}{v}*v

d*v=m

Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

  • A cubic centimeter is equal to a milliliter.
  • Therefore, 45 cubic centimeters also equals 45 milliliters.

d= 0.65 \ g/mL\\v= 45 \ mL

Substitute the values into the formula.

0.65 \ g/mL * 45 \ mL=m

Multiply. Note the milliliters, or mL will cancel out.

0.65 \ g * 45=m

29.25 \ g=m

The mass of the wood is 29.25 grams.

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Calculate the atomic mass of gallium, symbol Ga. Gallium has two isotopes: Ga-69 and Ga-71. The relative abundance of Ga-69 is 6
amm1812

Answer:

The atomic mass of gallium (Ga) = <u>69.723 g/mol</u>

Explanation:

Given: Two isotopes of Gallium (Ga) are Gallium-69 (⁶⁹Ga) and Gallium-71 (⁷¹Ga)

<u>For ⁶⁹Ga: </u>

Relative abundance = 60.12% = 60.12 ÷ 100 = 0.6012; Atomic mass = 68.9257 g/mol

<u>For ⁷¹Ga:</u>

Relative abundance = 39.88% = 39.88 ÷ 100 = 0.3988; Atomic mass = 70.9249 g/mol

∴ The atomic mass of Ga = (Relative abundance of ⁶⁹Ga × Atomic mass of ⁶⁹Ga) + (Relative abundance of ⁷¹Ga × Atomic mass of ⁷¹Ga)

⇒ Atomic mass of Ga = (0.6012 × 68.9257 g/mol) + (0.3988 × 70.9249 g/mol) = <u>69.723 g/mol</u>

<u>Therefore, the atomic mass of gallium (Ga) = 69.723 g/mol</u>

8 0
3 years ago
how much energy would it take to heat a section of the copper tubing that weights about 660.0 gram, from 12.93 degree Celsius to
expeople1 [14]

Answer:

                      Q  =  2647 J

Explanation:

                    Specific heat capacity is the amount of energy required by one Kg of a substance to raise its temperature by 1 °C.

In thermodynamics the equation used is as follow,

                                                 Q  =  m Cp ΔT

Where;

           Q  =  Heat  =  ?

           m  =  mass  =  660 g

           Cp  =  Specific Heat Capacity  =  0.3850 J.g⁻¹.°C⁻¹

           ΔT  =  Change in Temperature  =  23.35 °C - 12.93 °C  =  10.42 °C

Putting values in eq. 1,

                            Q  =  660 g × 0.3850 J.g⁻¹.°C⁻¹ ×  10.42 °C

                            Q  =  2647 J

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3 years ago
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Solar eclipse only i believe
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