The value of f is 348 pounds.
Given
At a big cat reserve, a male Bengal tiger weighs more than a female Bengal tiger.
The male tiger weighs 445 pounds.
The difference in the weight of the tigers is 97 pounds.
<h3>Difference;</h3>
The meaning of DIFFERENCE is the quality or state of being dissimilar or different.
The zookeeper created the bar diagram and the equation below is given as:
On solving the equation the value of f is;
Hence, the value of f is 348 pounds.
To know more about the differences click the link given below.
brainly.com/question/11572024
Answer:
between 21 and 30 pounds in shelter A between 18 and 28 pounds in shelter B
Step-by-step explanation:
One half of the dogs in each shelter points at the the upper 50% of the dog weight. This point is marked by the median value up to the maximum weight value.
The median value is the point marked inside the box on a boxplot and the maximum value is the upper end or the endpoint of the whisker.
For SHELTER A:
Median = 21
Maximum = 30
Hence, For shelter A, it is the interval between 21 and 30
For shelter B:
Median = 18
Maximum = 28
Hence, it is the interval between 18 and 28
Answer:
We know area of a square = side× side
Let the length of each side of the square be s
s×s= 121 sq ft
s²= 121 sq.ft
s=√121
s= 11 ft
11 ft long and wide
Hi there!
These can probably be done on your own. You just gotta know what to do! :)
Let's take #1 for example. You (or maybe a classmate/teacher showed you?) plotted the points. Mark each point with the given letter, so you don't get lost. Then, you reflected it over the y-axis.
Think of it as a mirror. Say you held a picture of a rhombus up to it. You would see the rhombus, yourself, and whatever was in the background reflected back at you. You step closer, the image steps closer. You turn the rhombus, and the image also turns. This principle can be used here!
So, keep doing what you're doing. Here's a step-by-step:
1.) Plot each point, and mark its name. For example, 'B' is (-6,7), and you write 'B' next to the point.
2.) Double check the point are exactly where they need to be
3.) Connect each point with a straight line. You can use a ruler, student ID, whatever as a straightedge, but it looks neater
4.) Draw a line for the axis. For example, if y=0, draw a straight line again there. (hint: that's the y-axis!)
5.) Double check that everything is right so far again. This is easy to mess up!
6.) Reflect each point over the axis. Another example, (-3, 2) becomes (3, 2). Mark this with an apostrophe (') to signal the point as prime, or the reflected point. For example, B becomes B' (B prime)
7.) Check one final time
If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one! :)
