Answer:
Step-by-step explanation:
In a static position, the sum of the forces is always 0.
so:
F1 = 480 N
F2 = -600 N
F3 = ?
F1 + F2 + F3 = 0
480 - 600 + F3 = 0
F3 = 120 N (the answer is positive, so the force acts in the same direction as F1)
7.37:
a. <em>W</em> follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

is chi-squared distributed with <em>n</em> d.f.. Here we have
and
.
b. <em>U</em> follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

is chi-squared distributed with <em>n</em> - 1 d.f..
c. <em>Y₆</em>² is chi-square distributed for the same reason as <em>W</em>, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then <em>U</em> + <em>Y₆</em>² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.
7.38:
a. Notice that

and see definition 7.2 for the <em>t</em> distribution. Since <em>Y₆</em> is normally distributed with mean 0 and s.d. 1, it follows that this random variable is <em>t</em> distributed with 5 degrees of freedom.
b. Similar manipulation gives

so this r.v. is <em>t</em> distributed with 4 degrees of freedom.
Answer:
5318582301
Step-by-step explanation:
Answer:
154 sq mm divided by 11 mm we get, 14 mm
Step-by-step explanation:
Given that: 154 sq mm divided by 11 mm.
Divide means 
then our statement becomes:

⇒
Divide numerator and denominator by 11 we get;

Therefore, 154 sq mm divided by 11 mm we get the result 14 mm