In a litter 2 out of 8 kittens are male what percent.of the kittens are female

Graph the equation. y=2x^2-8x+3y=2x 2 −8x+3

Gwar [14]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The equation can be rewritten to vertex form, so you can tell the vertex is at (2, -5). The leading coefficient of 2 means the points will be twice as far apart vertically than they would be if the leading coefficient were 1. A couple of points are shown in the attached.

y = 2(x^2 -4x) +3

y = 2(x^2 -4x +4) +3 -8 . . . . . . complete the square

y = 2(x -2)^2 -5 . . . . . . . . . . . . finish putting in vertex form

8 0

3 years ago

An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box= $lbh=x^2h$

$4=x^2h$

$h=\frac{4}{x^2}$

Now, surface area of box,A= $x^2+4xh$

$A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}$

$\frac{dA}{dx}=2x-\frac{16}{x^2}$

$\frac{dA}{dx}=0$

$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

$x^3=8$

$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h= $\frac{4}{2^2}=1 ft$

Hence, the dimension of box= $2ft\times 2ft\times 1ft$

5 0

3 years ago

Micaela is 2 years older than Sam. In 4 years, the sum of their ages will be 40. How old is Micaela now? Describe and fix any er

Verdich [7]

Answer:

Micaela is 17

Step-by-step explanation:

s+2=m

(s+2+4)+(s+4)=40

(s+6)+(s+4)=40

2s+10=40

40-10=30

2s=30

30/2= 15

s=15

{s+2=m}

15+2=m

m=17

5 0

3 years ago

Read 2 more answers

Gabe rounds 9.456 to the nearest hundredth. Then, he rounds the result to the nearest tenth. Last, he rounds that result to the

larisa86 [58]

Answer:

390

Step-by-step explanation:

.

4 0

3 years ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

4 years ago