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kherson [118]
3 years ago
15

What is the value of x ? please explain ! ill mark brainlest !!

Mathematics
1 answer:
Sedaia [141]3 years ago
3 0

Answer

ehfiefewfiehfwenfkwe good luck

Step-by-step explanation:

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Ross needs to have a procedure done. Because he is over 65, he is on medicare. Their plan says that according to their plan thei
artcher [175]
300=(1/6*7/8)x
300=7/48x
300*48=7x
14400=7x
2057=x

So the answer is B

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4 0
3 years ago
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One-sixth the sum of eight and a number
Aleks04 [339]

Step-by-step explanation:

Let the number be x.

<u>1</u><u> </u> =8 + x

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6×<u>1</u>=6×8+6×x

6

1=48+6x

1-48=6x

<u>-</u><u>4</u><u>7</u>=<u>6</u><u>x</u>

6. 6 x = -7 <u>5</u>

6

x is equal to minus seven whole number five divided by six.

7 0
3 years ago
PLEASE HELP GIVING BRAINLIEST
Alexeev081 [22]

Answer:

(-5-3/2,3+1/2)

(-13/2,7/2)

option A is correct

Step-by-step explanation:

Hope it helps

4 0
3 years ago
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The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
liq [111]

Answer:

  • <u>Option B. 59%</u>

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

  • A(t)=136(1.123)^{4t}

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

8 0
3 years ago
I need help!!! ASAP!!!! !!!!!
GalinKa [24]

Answer:

1.

Volume= 729cm^3

Height= 9cm^2

Area of Base= 81cm^2

2.

Volume=450m^3

Height= 3m^2

Area of Base=150m^2

3.

Volume= 480 cm^2

Area of base=75cm^2

Height= 8cm^2

4.

Volume =120in^3

Area of Base=20in^2

Height= 6in^2

Step-by-step explanation:

Volume = (length) Times (Width) Times (Height)

Area os base = (Length) Times (width)

3 0
2 years ago
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