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Sedaia [141]
4 years ago
6

A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh

en the plate separation is then doubled? It becomes four times larger. It becomes one-half as large. It stays the same. It becomes two times larger.
Chemistry
1 answer:
bekas [8.4K]4 years ago
5 0

Answer:

The correct option is: It becomes one-half as large.

Explanation:

The energy stored in a capacitor is inversely proportional to the distance between plates.

If the plate separation (distance between plates) is doubled, it means the Energy stored will be halved. That is, the energy stored becames one-half as large.

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Explanation:

C_7H_6O_2\rightarrow H^+C_7H_5O_2^-

 cM                0             0

c-c\alpha    c\alpha      c\alpha  

So dissociation constant will be:

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Putting in the values we get:

6.3\times 10^{-5}=\frac{(0.32\times \alpha)^2}{(0.32-0.32\times \alpha)}

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b) Given c= 0.00014 M and K_a=6.3\times 10^{-5}

\alpha = ?

Putting in the values we get:

6.3\times 10^{-5}=\frac{(0.00014\times \alpha)^2}{(0.00014-0.00014\times \alpha)}

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