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SOVA2 [1]
3 years ago
6

Adding or removing thermal energy causes a change in state of matter. O True O False

Chemistry
2 answers:
drek231 [11]3 years ago
6 0
TRUE :))) !!!! yup here ya go
Romashka [77]3 years ago
4 0

Answer:"You can change an object's state of matter by adding or removing thermal energy. When you add thermal energy to an object, these things can happen: Particles move faster (increased kinetic energy). Particles get farther apart (increased potential energy)."

Explanation:

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BTW IT IS SCIENCE
Sliva [168]
The answer is A warm air rises cool air sinks

4 0
3 years ago
Read 2 more answers
Rubidium has two naturally occurring isotopes, rubidium -85 ( atomic mass = 84.9118 amu; abundance = 72.15%) and rubidium -87 (a
son4ous [18]

Answer:

The answer to your question is: 85.458 amu

Explanation:

data

Rubidium-85   A = 84.9118 amu   abundance = 72.15%  

Rubidium - 87  A = 86.9092 amu abundance = 27.85%

Atomic weight = ?

Atomic weight = 84.9118(0.7215) + 86.9092(0.2785)

Atomic weight = 61.2538 + 24.2042

Atomic weight = 85.458 amu

6 0
4 years ago
A 0.130 mole quantity of NiCl 2 is added to a liter of 1.20 M NH 3 solution. What is the concentration of Ni 2 + ions at equilib
rosijanka [135]

This is an incomplete question, here is a complete question.

A 0.130 mole quantity of NiCl₂ is added to a liter of 1.20 M NH₃ solution. What is the concentration of Ni²⁺ ions at equilibrium? Assume the formation constant of Ni(NH₃)₆²⁺ is 5.5 × 10⁸

Answer : The concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

Explanation :  Given,

Moles of NiCl_2 = 0.130 mol

Volume of solution = 1 L

Concentration=\frac{Moles }{Volume}

Concentration of NiCl_2 = Concentration of Ni^{2+} = 0.130 M

Concentration of NH_3 = 1.20 M

K_f=5.5\times 10^8

The equilibrium reaction will be:

                      Ni^{2+}(aq)+6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}

Initial conc.    0.130       1.20                     0

At eqm.             x       [1.20-6(0.130)]      0.130

                                   = 0.42

The expression for equilibrium constant is:

K_f=\frac{[Ni(NH_3)_6^{2+}]}{[Ni^{2+}][NH_3]^6}

Now put all the given values in this expression, we get:

5.5\times 10^8=\frac{(0.130)}{(x)\times (0.42)^6}

x=4.31\times 10^{-8}

Thus, the concentration of Ni^{2+} ions at equilibrium is, 4.31\times 10^{-8}

7 0
4 years ago
Which option is correct ?
Norma-Jean [14]
B: Convection... Because it is a Repeated action of heat just like Convection heating
7 0
3 years ago
Get ready for the wave of screenshots :>
Reil [10]

Answer:

okay let me know when i can help, ill be happy too help

6 0
3 years ago
Read 2 more answers
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