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Viktor [21]
3 years ago
14

Which is usually true of Archaea?

Biology
1 answer:
rusak2 [61]3 years ago
8 0

Answer: E. All of the choices are correct.

Explanation:

Archaea are the prokaryotic organisms. These are single celled microorganisms. These organisms do not have a nucleus and their cell wall is rigid so as to sustain the cell in harsh environmental condition. These organisms reproduce by binary fission.The archeal DNA replicates and the two strands are separated and distributed to the two daughter cells. These organisms can be seen in different shapes such as spirals, spheres and rods.  

     

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A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
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Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
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