Answer:
The solution is n=1
Step-by-step explanation:
I hope you mean
4/5n-3/5=1/5n
if so then here's the solution
5n×4/5n-3/5×5n=1/5n×5n
4-3n=1
4-1=3n
3n=3
n=1
Answer:
c,d,e,f
Step-by-step explanation:
mark me brainliest
Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Answer:
Sorry but you have the y and x mixed up
Step-by-step explanation:
You have them mixed up
The answers are #1 45 #2 24 #3 10