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bonufazy [111]
3 years ago
10

Can u plz help me out​

Mathematics
2 answers:
Assoli18 [71]3 years ago
4 0

Answer:

c

Step-by-step explanation:

dont take my word on it im not positive but. i believe its c bc the line represents x and your first point is on -6 and gets greater so x should be greater or equal to -6

Alona [7]3 years ago
4 0

Answer:

The answer is D.

Step-by-step explanation:

There is a close dot proceeding in the direction in which numbers increase.  The dot is on the number -6 so D is the answer.

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What is the solution to the equation fraction 4 over 5 n minus fraction 3 over 5 equals fraction 1 over 5 n?
Andreas93 [3]

Answer:

The solution is n=1

Step-by-step explanation:

I hope you mean

4/5n-3/5=1/5n

if so then here's the solution

5n×4/5n-3/5×5n=1/5n×5n

4-3n=1

4-1=3n

3n=3

n=1

6 0
3 years ago
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Select all values of x that make the inequality true: (x ≥ -1)
FromTheMoon [43]

Answer:

c,d,e,f

Step-by-step explanation:

mark me brainliest

7 0
3 years ago
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2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA
professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0
1 year ago
Is my answer correct? If its not, would you mine telling me what is correct?
Luden [163]

Answer:

Sorry but you have the y and x mixed up

Step-by-step explanation:

You have them mixed up

6 0
3 years ago
Read 2 more answers
I need the answers to #1,#2 and #3
Ede4ka [16]
The answers are #1 45 #2 24 #3 10
6 0
3 years ago
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