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d1i1m1o1n [39]
3 years ago
15

Please solve for b.

Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0
For this one.
-\frac{9}{3}+b=-1 \ \textgreater \  \mathrm{Divide\:the\:numbers:}\:\frac{9}{3}=3 \ \textgreater \  -3+b=-1

\mathrm{Add\:}3\mathrm{\:to\:both\:sides} \ \textgreater \  -3+b+3=-1+3 \ \textgreater \  Simplify \ \textgreater \  b=2

Hope this helps!
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how many 4 digit numbers n have the property that the 3 digit number obtained by removing the leftmost digit is one ninth of n
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Answer:

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Step-by-step explanation:

We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.

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Let the thousands digit be 'd'. Then we want to find the integer solutions to ...

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  n -n/9 = 1000d . . . . . . add 1000d -n/9

  8n = 9000d . . . . . . . . multiply by 9

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The values of d that will give a suitable 4-digit value of n are 1 through 7.

When d=8, n is 9000. Removing the 9 gives 0, not 1000.

When d=9, n is 10125, not a 4-digit number.

There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.

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2 years ago
What is the correct answer
anzhelika [568]
A and D
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