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3 years ago

23 times what equals 500

Mathematics

1 answer:

Anna11 [10]3 years ago

3 0

Answer:

23 times 22 equals 506 but 23 times nothing can equal 500 thats what i think hope it helps in someway ig idk

Step-by-step explanation:

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Can someone help me with this? This is my summer school work, i'm failing miserably and I don't understand this at all.

svetoff [14.1K]

Answer:

Step-by-step explanation:

the equation formula is y = mx+b

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x is always x

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4 years ago

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A bathtub emptied 25 liters of water into 1/3 of a minute.How many liters of water does the bath drain per minute

kaheart [24]

Answer: 8 in a liter so to fill it up 25 divide by 1/3 which will equal 5 liters

Step-by-step explanation: add

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3 years ago

Find the value of x ?

Digiron [165]

Answer: 60 please give brainliest

Step-by-step explanation:

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2 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

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3 years ago

Solve for x.<br> Put your answer in decimal form.

liberstina [14]

Answer:

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Step-by-step explanation:

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3 years ago