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babunello [35]
3 years ago
11

Factoring with Algebra Tiles Represent the quadratic polynomial 2x2 + x – 6 using algebra tiles and determine the equivalent fac

tored form. The number of zero pairs needed to model this polynomial is . The equivalent factored form is .
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

Two zero pair

f(x)=(2x-3)(x+2)    

Step-by-step explanation:

We are given the following quadratic equation:

f(x) = 2x^2+x-6

Since, this a quadratic equation we would have two zero pairs for this model.

Factored form of polynomial:

f(x) = 2x^2+x-6\\f(x)=2x^2+ 4x -3x -6\\f(x)=2x(x+2)-3(x+2)\\f(x)=(2x-3)(x+2)

is the required factored form of the given polynomial.

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Short answer: - 1
The first thing you should do is draw this or get a program to do it. I use desmos. It is included. The graph shows one complete cycle every 2*pi intervals (or 360 degrees.)

You will find no lower value that y = - 1 (nor any value greater than y = 1)


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Trihao is driving from cambridge to london Assume the distance between cambridge and london is 100 km Given that trihao drives a
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average speed equals distance over time 100/80 will give you 5/4

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2 years ago
You are given a 16-bit binary integer X= (1110 0100 0111 1010)2 . Convert X to decimal if:
podryga [215]

Step-by-step explanation:

a). The decimal numbers is equal to the sum of binary numbers $(b_n)$  times their powers of   $ 2(2^n) .$

That is,

$ b_n \times 2^n + b_{n-1} 2^{n-1}+ ..... + b_02^0 $

$\therefore (1110 \ \ 0100 \ \ 0111 \ \ 1010)_2 $

=  $ (0 \times 2^0) + (1 \times 2^1) + (0 \times 2^2) + (1 \times 2^3) + (1 \times 2^4) + (1 \times 2^5) + (1 \times 2^6)  + ( 0 \times 2^7) + (0 \times 2^8) + (0 \times 2^9) + (1 \times 2^{10} ) $$  + (0 \times 2^{11}) + (0 \times 2^{12}) + (1 \times 2^{13}) + (1 \times 2^{14})+ (1 \times 2^{15})$

= 58490

b).

The left most bit of the number represents the sign of the number. If bit = 1, the number is negative else if the bit is 0, the number is positive.

All the remaining bits (i.e all the bits except the leftmost bit) represent the magnitude of the number.

  Now, X = 1110 0100 0111 1010

  left most bit = 1 => number is negative

  remaining bits Y = 110 0100 0111 1010

  converting Y to decimal => Y = 25722

c).

Check the leftmost bit(lmb) of the number

if leftmost bit is 0 => convert do the binary to decimal conversion

if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add a negative sign / multiply by -1

 Now, X = 1110 0100 0111 1010

left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

multiplying Y with -1 => Y = -7045

Therefore, one's complement of X to decimal is -7045

Thus, X = -25722 in decimal.

d).

Check the leftmost bit(lmb) of the number

  if leftmost bit is 0 => convert do the binary to decimal conversion

  if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add 1 to the converted number

  4. Add a negative sign / multiply by -1

Now, X = 1110 0100 0111 1010

left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

Adding 1 to Y => Y = 7046

multiplying Y with -1 => Y = -7046

Thus, two's complement of X to decimal is -7046

7 0
3 years ago
Help please marking brainlist!!
dangina [55]
Answer should be the second one, B
6 0
3 years ago
How do I solve this
Pani-rosa [81]

Answer: you alredy solved it

Step-by-step explanation:

4 0
3 years ago
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