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MatroZZZ [7]
3 years ago
12

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

s. The distribution of the number of daily requests is bell-shaped and has a mean of 40 and a standard deviation of 8. Using the empirical rule, what is the approximate percentage of lightbulb replacement requests numbering between 24 and 40
Mathematics
1 answer:
damaskus [11]3 years ago
5 0

Answer:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

Step-by-step explanation:

For this problem we have the following parameters given:

\mu = 40, \sigma =8

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

z=\frac{X-\mu}{\sigma}

And replacing we got:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

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