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Fudgin [204]
3 years ago
12

Determine the area of the figure on the coordinate grid. Round to the nearest hundredth if needed. Show all work to receive cred

it.

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

I can't currently fully answer, hoping someone can come along and help-

Step-by-step explanation:

separate the shape into 3 triangles and 1 rectangle and then add all the areas together

area of a triangle is 1/2 base times height and area of a rectangle is length multiplied by width

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Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.
makvit [3.9K]
<h3>Answer: 7366.96 dollars</h3>

========================================================

Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

-------

Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

12000 = P(1.05)^(10)

12000 = P(1.62889462677744)

12000 = 1.62889462677744P

1.62889462677744P = 12000

P = 12000/1.62889462677744

P = 7366.95904248911

P = 7366.96

6 0
3 years ago
PRECALCULUS please help​
sergejj [24]

Answer:

<h2>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h2>

Step-by-step explanation:

f(x) =  \frac{2x + 6}{3x}  \\  \\ g(x) =  \frac{ \sqrt{x}  - 8}{3x}

To find ( f - g)(x) , subtract g(x) from f(x)

That's

( f - g)(x) =  \frac{2x + 6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}

Since they have a common denominator that's 3x we can subtract them directly

That's

\frac{2x  +  6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}    =  \frac{2x  + 6 - ( \sqrt{x} - 8) }{3x}  \\  =  \frac{2x + 6 -  \sqrt{x} + 8 }{3x}  \\  =  \frac{2x -  \sqrt{x} + 6 + 8 }{3x}

We have the final answer as

<h3>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h3>

Hope this helps you

6 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
Given that a = -1, b=2 and c= -3 ,find the value of a(b2+c2)
KiRa [710]

Answer:

a(b^{2}+c^{2}) = = -13

Step-by-step explanation:

Given that a = -1, b=2 and c= -3

find the value of a(b^{2}+c^{2})

Just substitute the values given for each variable

a(b^{2}+c^{2}) = (-1)(2^{2}+(-3)^{2}) ; do the exponents first

a(b^{2}+c^{2}) = (-1)(4+9)=(-1)(13) ; now add inside the parenthesis;

a(b^{2}+c^{2}) = -13 ; and multiply by -1

7 0
3 years ago
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