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3 years ago

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A yellow and green car traveled 400 miles to Dayton, OH. The green car made the trip in 10 hours. The yellow arrived in 8 hours.

Calculate the speed of each car and tell which car was faster. (s=d/t)
A)The green car was faster. Green traveled at a speed of 50 mph while yellow was traveling at an average of 40 mph.

B)The green car was faster since it arrived in 10 hours.

C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

D)The yellow car was faster since it was traveling at 40 mph

2 answers:

elixir [45]3 years ago

4 0

Answer: C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

Explanation:

The speed of each car is defined as:

$v=\frac{d}{t}$

where d is the distance traveled by the car and t is the time taken.

For the yellow car, d=400 mi and t=8 h, so its speed is

$v=\frac{400 mi}{8 h}=50 mph$

For the green car, d=400 mi and t=10 h, so its speed is

$v=\frac{400 mi}{10 h}=40 mph$

So, the correct choice is

C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

forsale [732]3 years ago

4 0

Answer:

C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

Explanation:

The speed is defined as ratio of distance covered with time:

$v = \frac{distance}{time}$

$v = \frac{d}{t}$

here

d = the distance traveled by the car and

t = the time taken.

For the yellow car,

d=400 mi

t=8 hours

so speed of yellow car is given as

$v_{yellow} = \frac{400}{8} = 50 mph$

For the green car,

d=400 mi

t=10 hours,

so speed of green car is

$v_{green} = \frac{400}{10} = 40 mph$

So, the correct choice is

C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

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