In Florida, the standard defined speed limit in a residential area is ____ mph.

1 answer:

7 0

The correct answer among the choices given is the last option. In Florida, the standard defined speed limit in a residential area is 30 mph. In the United States, the speed limit in urban areas is 30 mph and in unpaved roads is 35 mph. In interstate roads the limit is at 70 mph.

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A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.

dsp73

Answer:

Explanation:

In friction, the coefficient of friction formula is expressed as;

$\mu = \frac{F_f}{R}$

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

$\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta$

Given

θ = 24°

$\mu = tan 24^0\\\mu = 0.445\\$

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

3 0

3 years ago

There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm

saul85 [17]

Answer:

spring D stretches the weakest

6 0

3 years ago

PLEASE HELPPP MEEE :((

Hoochie [10]

Power = work / time --> time = work / power = 3600 J / 275 watts = 13.1 seconds.

Make me brainliest plz

4 0

3 years ago

A person who weighs 150 pounds on Earth would weigh ____ pounds on the moon.

enot [183]

Answer:

25lb

Explanation:

You haven't changed (you are made up of the same atoms), but the force exerted on you is different. Physicists like to say that your mass hasn't changed, only your weight.

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3 years ago

Pun zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que caminar hay un insta

Mars2501 [29]

Answer:

Las presión ejercida por los tacos sobre el suelo es 900 libras por pulgada cuadrada.

Explanation:

Según la Física, comprendemos que la presión es igual a la fuerza dividida por área. En este caso, el peso de la persona dividida por área total de los tacos de los zapatos de golf suponiendo una distribución uniforme de la fuerza. Es decir:

$\sigma = \frac{W}{n\cdot A_{T}}$ (Eq. 1)