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kogti [31]
4 years ago
11

Please help me this is a test and it needs to be done in a few​

Physics
2 answers:
Amanda [17]4 years ago
7 0

Answer:

I think A because astroids are stronger than a crash. Hope I helped! :)

Explanation:

Lelu [443]4 years ago
5 0

Answer:

aaaaa

Explanation:

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The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific
dmitriy555 [2]
<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

<h2>Why?</h2>

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

KineticEnergy=\frac{1}{2}mv^{2}

Where,

m, is the mas of the object

v, is the speed of the object.

Now, we are given:

mass=m=6.8kg\\speed=v=5\frac{m}{s}

So, substituting and calculating the kinetic energy of the object, we have:

KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}

KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})

KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}

KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0
3 years ago
Read 2 more answers
A fighter plane flying at constant speed 420 m/s and constant altitude 3300 m makes a turn of curvature radius 11000 m. On the g
Arada [10]

Answer:

"Apparent weight during the "plan's turn" is  519.4 N

Explanation:

The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is \mathrm{a}_{\mathrm{n}}=\frac{v^{2}}{R}

Given that,

v = 420 m/s

R = 11000 m

Substitute the values in the above equation,

a_{n}=\frac{420^{2}}{11000}

a_{n}=\frac{176400}{11000}

a_{n}=16.03 \mathrm{m} / \mathrm{s}^{2}

It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vectorW_{\mathrm{app}}=m(\text { vector } g \text { -vector a })

In magnitude,

| \text { vector } g-\text { vector } a |=\sqrt{\left(g^{2}+a^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{\left(9.8^{2}+16.03^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{(96.04+256.96)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{353}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=18.78 \mathrm{m} / \mathrm{s}^{2}

Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector

\mathrm{W}_{\mathrm{app}}=(18.78 \mathrm{m} / \mathrm{s}^ 2)(53 \mathrm{kg})=995.77 \mathrm{N}

Which is quite heavier than his/her true weigh of 519.4 N

7 0
4 years ago
Read 2 more answers
A 10.00 kg mass is attached to a 250N/m spring and set into vertical oscillation. When the mass is 0.50m above the equilibrium i
Paraphin [41]

assuming the reference line to measure the height for gravitational potential energy lying at the equilibrium position

m = mass attached to the spring = 10.00 kg

k = spring constant of the spring = 250 N/m

h = height of the mass above the reference line or equilibrium position = 0.50 m

x = compression of the spring = 0.50 m

v = speed of mass = 2.4 m/s

A = maximum amplitude of the oscillation

v' = speed of mass at the maximum amplitude location = 0 m/s

using conservation of energy between the point where the speed is 2.4 m/s  and the highest point at which displacement is maximum from equilibrium

kinetic energy + spring potential energy + gravitational potential energy = kinetic energy at maximum amplitude + spring potential energy at maximum amplitude  + gravitational potential energy at maximum amplitude

(0.5) m v² + m g h + (0.5) k x² = (0.5) m v'² + m g A + (0.5) k A²

inserting the values

(0.5) (10) (2.4)² + (10) (9.8) (0.50) + (0.5) (250) (0.50)² = (0.5) (10) (0)² + (10) (9.8) A + (0.5) (250) A²

109.05 = (98) A + (125) A²

A = 0.62 m

3 0
3 years ago
A bicycle is heading West. It goes 5000m in 500s what's its velocity
dybincka [34]
There are several information's of immense importance already given in the question. Based on the given information's the answer to the question can easily be determined.
Distance covered by the bicycle = 5000 meter
Time taken by the bicycle to reach the distance = 500 second.
Velocity of the bicycle = Distance / Time taken
                                   = 5000/500 meter/second
                                   = 50 meter/second
So the velocity of the bicycle is 50 meter per second. I hope the procedure is clear enough for you to understand. In future you can always use this procedure for solving similar problems.
8 0
3 years ago
Generators are device that convert_____energy into____energy
KiRa [710]

Answer:

A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy.

Explanation:

5 0
4 years ago
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