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3 years ago

1 A thing ring has a mass of 6kg and a radius of 20cm. calculate the rotational inertia.

Physics

1 answer:

marissa [1.9K]3 years ago

7 0

Answer:

2400kgm²

Explanation:

Rotational inertia=mass x radius²

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To add to the complexity, those precious atoms face the peril of disintegrating into the void. Luckily, by now, they are feeling

miskamm [114]

Answer:

B The most basic atoms were formed due to the force of gravity.

Explanation:

Since the statement says that the atoms could have faced the peril of disintegrating into the void, this means that, they could have been destroyed by movement away into the void.

But, it also says that by now, they are feeling the influence of gravity to bring them safely together. This statement shows that gravity brings them (the atoms) together and thus doesn't allow them disintegrate into the void.

<u>So, a reader can thus infer that the most basic atoms were formed due to the force of gravity since it doesn't allow the atoms disintegrate into the void.</u>

So, B is the answer.

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3 years ago

A hot brass plate is having its upper surface cooled by impinging jet of air at temperature of 15°c and convection heat transfer

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200 degrees because I need the points

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3 years ago

A series RLC circuit has a resonant frequency = 6.00 kHz. When it is driven at a frequency = 8.00 kHz, it has an

ANEK [815]

The resistance (R) of the circuit is 707.1 ohms and the inductance (L) is 0.032 H.

<h3>Resistance of the circuit</h3>

For the phase constant of 45⁰, impedance is equal to the resistance of the circuit.

$Z= R\sqrt{2} \\\\R = \frac{Z}{\sqrt{2} } \\\\R = \frac{1000}{\sqrt{2} } = 707.1 \ ohms$

<h3>Resonant frequency</h3>

$f = \frac{1}{2\pi \sqrt{LC} } \\\\6000 = \frac{1}{2\pi \sqrt{LC} } \\\\2\pi(6000) = \frac{1}{\sqrt{LC} } \\\\\sqrt{LC} = \frac{1}{2\pi (6000)} \\\\LC = (\frac{1}{2\pi (6000)})^2\\\\LC = 7.034 \times 10^{-10} \\\\ C = \frac{7.034 \times 10^{-10} }{L} ---(1)$

<h3>At driven frequency</h3>

$X_l- X_c = R\\\\\omega L - \frac{1}{\omega C} = 707.1\\\\2\pi f L - \frac{1}{2\pi fC} = 707.1\\\\2\pi (8000) L - \frac{1}{2\pi (8000) C } = 707.1\ \ --(2)\\\\$

<em>solve 1 and 2 together</em>

$2\pi(8000) L - \frac{L}{2\pi (8000)(7.034 \times 10^{-10})} = 707.1\\\\50272L - 28279.48L = 707.1\\\\L = 0.032 \ H$

Learn more about impedance of RLC circuit here: brainly.com/question/372577

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3 years ago

Which illusion or test was most difficult for you to perceive correctly? Why do you think this particular illusion was so challe

Alecsey [184]

Answer:

test 5 seemed to be the hardest for me to perceive in account i only saw three f's when there was indeed 6 it was very difficult to find the f's even going very slowly.

Explanation:

correct on edge

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3 years ago

Find the gravitational potential at a point on the earth surface. Take mass as of earth as 5.98×10^24kg,it's radius as6.38×10^6n

andrew-mc [135]

Answer:

$-6.25\cdot 10^7 J$

Explanation:

The gravitational potential at a point on the Earth surface is given by:

$U=-\frac{GM}{R^2}$

where

G=6.67×10^-11Nm^2kg^-2 is the gravitational constant

M=5.98×10^24kg is the Earth's mass

R=6.38×10^6 m is the Earth's radius

Substituting the numbers into the equation, we find

$U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J$

5 0

3 years ago

1 A thing ring has a mass of 6kg and a radius of 20cm. calculate the rotational inertia. ​

1 A thing ring has a mass of 6kg and a radius of 20cm. calculate the rotational inertia.