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DanielleElmas [232]
3 years ago
16

Carson wants to install wallpaper on the wall in his bedroom with the shape and dimensions shown below. To determine the area of

the wall, he divides it into a triangle and a rectangle. What are the dimensions of the triangle? 11 ft by 12 ft 3 ft by 12 ft 3 ft by 11 ft 12 ft by 14 ft
Mathematics
2 answers:
Firlakuza [10]3 years ago
4 0

Answer:

II think the answer might be 12ft by 11ft i'm not sure

Step-by-step explanation:

Inga [223]3 years ago
3 0

Answer:

12ft by 11ft

Step-by-step explanation:

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stellarik [79]

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(x,y)=(-11,-19)

Step-by-step explanation:

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1.65

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3 years ago
Please help me thank you
VashaNatasha [74]
The answer to the first one is 9√5

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4 0
3 years ago
Write a quadratic function in vertex form whose graph has the vertex (5,−2) and passes through the point (7,0).
Hatshy [7]

The quadratic function in vertex form is y=\frac{1}{2} (x-5)^{2}-2.

Solution:

The equation of a quadratic in  vertex form  is y=a(x-h)^{2}+k.

where  (h, k) are the coordinates of the vertex and "a"  is a multiplier.

Here (h, k) = (5, –2)

Substitute this in the vertex form.

y=a(x-5)^{2}+(-2)

y=a(x-5)^{2}-2 – – – – (1)

Passes through the point (7, 0).

Here x = 7 and y = 0.

Substitute this in equation (1), we get

0=a(7-5)^{2}-2

0=4a-2

Add 2 on both sides.

2 = 4a

Divide 2 on both sides, we get

$a=\frac{1}{2}

Substitute the value of a in equation (1),

$y=\frac{1}{2} (x-5)^{2}-2

The quadratic function in vertex form is y=\frac{1}{2} (x-5)^{2}-2.

8 0
3 years ago
The bases of a trapezoid are 11 meters and 14 meters. Its height is 10 meters. What is the area of the trapezoid?
zhuklara [117]
A=\frac{a+b}{2}h
Area:
\frac{11+14}{2} x 10 = 125m^3

Hope this helps.
8 0
3 years ago
Read 2 more answers
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