Answer:
the 4s subshell is lower in energy than the 3d subshell
Explanation:
In the element number 24 which is chromium
the electronic configuration should be according to Aufbau principle
will be =
but in reality it is =
The 6 electrons in the outermost shell will be divided as 5 in 3d subshell and 1 in 4s shell, because half filled orbital will be more stable than .
In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:
mass of gasoline= density * volume
mass of gasoline= 0.749g/ml * (1 pound/453.592grams) * 3785.41ml/gallon * 19.2 gallon= 120 pounds
The name of Pb(NO3)2 is lead (II) nitrate and its bond type is ionic bond. Details about bonding can be found below.
<h3>What is ionic bonding?</h3>
Ionic bond is a type of chemical bond where two atoms or molecules are connected to each other by electrostatic attraction.
According to this question, the chemical formula of lead (II) nitrate is given as follows: Pb(NO3)2.
The two constituent ions in this compound are as follows: Pb2+ and NO3-. They are bonded by an ionic bond.
Therefore, the name of Pb(NO3)2 is lead (II) nitrate and its bond type is ionic bond.
Learn more about ionic bond at: brainly.com/question/11527546
#SPJ1
You didn't put a + charge on one of the Ag. It has to be on the left side
2H2O + MnO2 ==> MnO4^- + 3e + 4H^+
Ag^+ + e ==> Ag^+
Those are the two BALANCED half reactions. Multiply equation 1 by 1 and equation 2 by 3 and add them.
This problem handles<em> boiling-point elevation</em>, which means we will use the formula:
ΔT = Kb * m
Where ΔT is the difference of Temperature between boiling points of the solution and the pure solvent (Tsolution - Tsolvent). Kb is the ebullioscopic constant of the solvent (2.64 for benzene), and m is the molality of the solution.
Knowing that benzene's boiling point is 80.1°C, we <u>solve for m</u>:
Tsolution - Tsolvent = Kb * m
80.23 - 80.1 = 2.64 * m
m = 0.049 m
We use the definition of molality to <u>calculate the moles of azulene</u>:
0.049 m = Xmoles azulene / 0.099 kgBenzene
Xmoles azulene = 4.87 x10⁻³ moles azulene
We use the mass and the moles of azulene to<u> calculate its molecular weight</u>:
0.640 g / 4.875 x10⁻³ mol = 130.28 g/mol
<em>A molecular formula that would fulfill that molecular weight</em> is C₁₀H₁₀. So that's the result of solving this problem.
The actual molecular formula of azulene is C₁₀H₈.