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Usimov [2.4K]
3 years ago
10

Which two particles are found in the nucleus of an atom?

Chemistry
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

Protons and neutrons

Explanation:

<em>Protons</em><em> </em><em>and</em><em> </em><em>neutrons</em><em> </em>are found in the <em>nucleus</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>atom</em>

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A solution that is 0.17m in HCHO2 and 0.11 Min in NaCHO2
Elanso [62]
Hello!

(Missing Previous Enunciate) <span>Use the Henderson-Hasselbalch equation to find the pH of: 

To solve this question we need the pKa of HCOOH, which is 3,75, now, we can apply the Henderson-Hasselbach equation:

</span>pH=pKa+ log( \frac{[HCOONa]}{[HCOOH]} )=3,75 + log( \frac{0,11M}{0,17M} )=3,56
<span>
So, the pH of a solution that is 0,17 M in HCHO</span>₂ and 0,11 M in NaCHO₂ is 3,56

Have a nice day!
7 0
3 years ago
What is the mass of 600.00 mL sample of seawater with a density of 1.025 g/mL?
kvasek [131]

Answer:

<h2>The answer is 615 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of seawater = 600 mL

density = 1.025 g/mL

The mass is

mass = 600 × 1.025

We have the final answer as

<h3>615 g</h3>

Hope this helps you

5 0
4 years ago
Determine the mass of NaOH needed to make 750.0mL of a 6.00 M solution of NaOH
fredd [130]

Answer: 180g

Explanation:

No of moles= volume ×molarity/1000

Volume is given as 750ml

Molarity is given as 6M

Substitute to get the mole

No of moles = 750×6/1000

No of moles= 4.5moles

Remember that

No of moles also = mass given/molar mass

Molar mass of NaOH

Na= 23

O=16

H=1

Molar mass = na +o+h

Molar mass =23+16+1

Molar mass=40g/mol

Substitute

No of moles = mass given/molar mass

Mass = 4.5×40

Mass = 180g

The mass of NaOH needed is 180g

3 0
3 years ago
Besides the concentration of the acid and its conjugate base, what else does one need to calculate the ph of a weak acid
Marta_Voda [28]
K_{a}, the acid disassociation constant. 
3 0
4 years ago
Can someone answer pls
USPshnik [31]
I think it would be 196
7 0
3 years ago
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